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garik1379 [7]
3 years ago
8

One of the students was removed from the survey and replaced with a different student’s data.

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

immma send you the link friend me on here Step-by-step explanation:

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HEYYYY GUYYYSSS HELPP MEEE, ILL MARK YOU BRAINIEST. PLEEEAAASEEEE thankkyouu
VikaD [51]

Answer:

Step-by-step explanation:

A dependent variable in an expression is one whose value can be determined only when the value of other variable (i.e independent) is known.

A. The cost at the fitness center depends on the number of months (x).

The cost is the dependent variable, and number of months (x) is the independent variable.

f(x) = 100 + 40x

Example, the cost paid for 12 months can be determined as;

f(12) = 100 + 40(12)

       = 100 + 480

       = 580

Thus, $580 would be paid for 12 months at the fitness center.

B. The lettuce is sold at $1.69 per pound. The cost depends on the number of pounds of lettuce bought.

The cost is the dependent variable, while the number of pounds of lettuce (x) bought is the independent variable.

So that;

f(x) = 1.69x

The cost of 10 pounds of lettuce can be determined as;

f(x) = 1.69(10)

     = 16.9

Thus, the cost of 10 lb of lettuce is $16.90.

6 0
3 years ago
Solve x − y = 5 for y.
AnnyKZ [126]

Answer:

-y=5-x

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Mr. Parker has 982 pounds of grain. He feeds 240 pounds ro his pigs and 460 to his cows. How much grain does he have left
denpristay [2]

Starting amount: 982 pounds of grain

Since Mr. Parker fed 240 pounds of grain to his pigs, subtract 240 pounds from 982 pounds of grain.

982 - 240 = 742

After feeding pigs: 742 pounds of grain

Mr. Parker fed another 460 pounds of grain to his cows from his 742 pounds, so subtract 460 pounds from 742 pounds.

742 - 460 = 282

After feeding pigs and cows: 282 pounds of grain

Mr. Parker has 282 pounds of grain left.

3 0
3 years ago
EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att
aliina [53]
y=x(x-2)^2
\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0
\implies x=\dfrac23,x=2

are the critical points, and judging by the picture alone, you must have b=\dfrac23 and a=2. (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

y'=3x^2-8x+4
\implies y''=6x-8

setting equal to 0 and finding the critical point:

6x-8=0\implies x=\dfrac86=\dfrac43

This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
4 0
4 years ago
Classify the following triangle, Check all that apply A Equilateral B, Acute C. Scalene D. Obtuse E. Isosceles. F.Right
Juli2301 [7.4K]

Answer:

D) obtuse

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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