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weqwewe [10]
3 years ago
12

Fill in the blank 23+48=71. 71-______=23

Mathematics
1 answer:
Shkiper50 [21]3 years ago
6 0
It's 48 because 23+48=71 So 71-48=23
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Please help! Will give Brainliest!!
Valentin [98]

Answer:

$133507.33

Step-by-step explanation:

x = number of 6 month periods

y = total money in account

After 10 years:

y = 300x(1.09)^x

y = 300(20)(1.09)^2^0

y = 6000(5.60441077)

y = 33626.46

After 18 years:

y = 33626.46(1.09)^x

y = 33626.46(1.09)^1^6

y = 33626.46(3.97030588)

y = 133507.33

6 0
3 years ago
What is the sum of a 56-term arithmetic sequence where the first term is 6 and the last term is 391?
Sati [7]
S_n=\dfrac{a_1+a_n}{2}\cdot n\\\\a_1=6;\ n=56;\ a_{56}=391\\\\subtitute\\\\S_{56}=\dfrac{6+391}{2}\cdot56=\dfrac{397}{2}\cdot56=397\cdot28=11,116
7 0
3 years ago
Read 2 more answers
Someone, please help me with this question.
Viefleur [7K]

Answer:

C.  95°

Step-by-step explanation:

Sumplementary angles sum 180°

144° + a = 180°

a = 180° - 144°

a = 36°

121° + b = 180°

b = 180° - 121°

b = 59°

The sum of internal angles of a triangle is 180°

a + b + c = 180°

36° + 59° + c° = 180°

c° = 180° - (36°+59°)

c° = 180° - 95°

c° = 85°

then:

c + n = 180°

85° + n = 180°

n = 180° - 85°

n = 95°

5 0
3 years ago
The circumference of Circle K is $\pi$ . The circumference of Circle L is $4\pi$ . Two circles, one labeled "Circle K" and the o
timurjin [86]

Answer:

Step-by-step explanation:

Given the circumference of Circle K = π

circumference of Circle L = 4π

Ratio of their circumferences = Ck/Cl

Ratio of their circumferences = π/4π

Ratio of their circumferences = 1/4 = 1:4

For their radii

C = 2πr

for circle k with circumference π

π = 2πrk

1 = 2rk

rk = 1/2

for circle l with circumference 4π

4π = 2πr

4 = 2r

r = 4/2

rl = 2

ratio

rk/rl = 1/2/2

rk/rl = 1/4 = 1:4

for the areas

Area of a circle = πr²

for circle k

Ak = π(1/2)²

Ak = π(1/4)

Ak = π/4

for circle l

Al = π(2)²

Al = 4π

Ratio of their areas

Ak/Al = π/4/(4π)

Ak/Al = π/16π

Ak/Al = 1/16 = 1:16

3 0
2 years ago
Where does the normal line to the parabola y = x − x2 at the point (1, 0) intersect the parabola a second time?
Ksivusya [100]
Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)

we just need the slope

take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1

the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation

solve for where y=x-1 and y=x-x² intersect

set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero

x-1=0
x=1
we got this point already

x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2

it intersects at (-1,-2)
7 0
3 years ago
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