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2 years ago

PLS HELP!!

Mathematics

1 answer:

schepotkina [342]2 years ago

3 0

Option a: Quadratic expression

Explanation:

The expression is $-2x^{2} +11$

Option a: Quadratic expression

The quadratic expression is an expression in which the highest power or degree of a variable is 2.

Thus, from the expression $-2x^{2} +11$ the highest power of the variable is 2.

Hence, the expression is quadratic

Option a is the correct answer.

Option b: Linear expression

The linear expression is of the form $y=mx+b$

Since, the expression $-2x^{2} +11$ is not of the form $y=mx+b$ , it is not a linear expression.

Hence, Option b is not the correct answer.

Option c: Cubic expression

The cubic expression is an expression in which the highest power or degree of a variable is 3.

Since, the expression $-2x^{2} +11$ does not have the highest power 3, it is not a cubic expression.

Hence, Option c is not the correct answer.

Option d: Exponential expression

The exponential expression indicates the number of times the base is used as a factor.

Since, the expression $-2x^{2} +11$ does not indicates the number of times the base is used as a factor, it is not exponential expression.

Hence, Option d is not the correct answer.

You might be interested in

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

2 years ago

The volume of a 10 ounce box of cheerios is 258.75in3. the length of the box is 4 inches less than the height and the width is 3

Marina86 [1]

Answer:

Height of the box = 11.5 in

Step-by-step explanation:

Let h be the height of the box.

Assuming the volume of the Box is $258.75\ in^3$ .