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Dafna1 [17]
3 years ago
8

Someone help me asap please.

Mathematics
1 answer:
zaharov [31]3 years ago
7 0

15. x ≤ -24

    x + 19 ≤ -5

    x ≤ -24

16. z > -12

    3z > -36

    z > -12

17. 185 + c > 410; c > 225


18.   C.

    x - 6 ≥ 1

    x ≥ 7

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The focus of a parabola is (-10, -7), and its directrix is x = 16. Fill in the missing terms and signs in the parabola's equatio
avanturin [10]
Answer: (y-3)^2= 52(x+7)

The focus is (-10, -7) and the directrix is x=16. The y-coordinate of the vertex should be same as the focus(k=-7). Then the x-coordinate of the vertex would be:
p + (-10)=  16 - p
2p= 16 + 10
p=26/2= 13

The x-coordinate of the vertex would be:
h= p+ (-10)
h= 13 - 10= 3

The vertex coordinate would be: (h, k)= (3, -7)
For a vertex (h, k), the formula for equation would be 
(y-k)^2=4 p(x-h)
(y-3)^2= 4*13(x--7)
(y-3)^2= 52(x+7)
7 0
3 years ago
Sara and Sam are each working on a science project in which they need to research the individual masses of the nine planets (inc
makkiz [27]

Answer:

2000 times

Step-by-step explanation:

Given

Sara:

Mercury = 3.302 * 10^{23

Saturn = 5.685 * 10^{26

Sam:

Mercury = 3.302 * 10^{29

Saturn = 5.685 * 10^{32

To determine the number of times, the mass of Saturn is greater than the mass of Mercury, we simply do the following:

Times = \frac{Saturn}{Mercury}

Using Sara's measurement; this gives:

Times = \frac{5.685 * 10^{26}}{3.302 * 10^{23}}

Apply law of indices

Times = \frac{5.685 * 10^{26-23}}{3.302}

Times = \frac{5.685 * 10^3}{3.302}

Times = 5.685/3.302 * 10^3

Times = 1.72 * 10^3

Approximate

Times = 2 * 10^3

Times = 2000

5 0
3 years ago
Lisa wants to buy a phone card for $5. Company X charges $0.37 for the first minute and $0.08 for each additional minute. Compan
lesya692 [45]
Company X - 5.00-.37=4.63/.08=57

You get 57 minutes for this company

Company Y - 5.00-.52=4.48/.14=32

You get 32 minutes for this company

Company X gives you more minutes for $5.00
6 0
3 years ago
What is the next term in this geometric sequence<br>5/6,5/9,10/27,20/81
Ghella [55]
a_1=\frac{5}{6};\ a_2=\frac{5}{9};\ a_3=\frac{10}{27};\ a_4=\frac{20}{81}\\\\\\q=a_2:a_1\\\\q=\frac{5}{9}:\frac{5}{6}=\frac{5}{9}\cdot\frac{6}{5}=\frac{2}{3}\\\\\\a_5=a_4\cdot q\\\\a_5=\frac{20}{81}\cdot\frac{2}{3}=\frac{40}{243}\to answer
3 0
3 years ago
Read 2 more answers
A boy spent 20% of his money on books and 20% of the remainder on food.If he had $2000 left, how much money did he have at first
DENIUS [597]

Answer:

\$3,125

Step-by-step explanation:

Let s represent the amount of money he initially started with.

After he spent 20% on books, he will have 100\%-20\%=80\% of his initial money left. We can represent this as 0.8s.

Following that, the boy spends 20% of the remainder of his money on food. Similarly, he will have 100\%-20\%=80\% of the remainder of money he had left after he purchased the books. Therefore, he ends up with 0.8(0.8s)=0.64s of his money left.

Since we're given that he had $2,000 after all these transactions, we have the following equation:

0.64s=\$2,000

Divide both sides by 0.64 to isolate and solve for s:

s=\frac{2,000}{0.64}=\boxed{\$3,125}

Therefore, the boy had $3,125 to begin with.

7 0
3 years ago
Read 2 more answers
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