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den301095 [7]
3 years ago
14

Whats the answer help please

Mathematics
1 answer:
Maslowich3 years ago
3 0

Answer:

the answer is D I think ...

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ankoles [38]
The answer to this is 3645
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3 years ago
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The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So
tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 \times 10^{-6}.

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........

where, n = number of trials (samples) taken = 18 Southwest flights

           r = number of success = at least 13 flights arrive late

          p = probability of success which in our question is probability that

                flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X \geq 13)

P(X \geq 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= \binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}

= \binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}

= 2.5196 \times 10^{-6}.

7 0
4 years ago
K=1/2mv^2 solve v answer <br><br><br><br><br> V=兀r^2h solve r answer
Alex17521 [72]
Ok so you first you move the 2h to the top and and 兀r is multiplied by ten of course and then you get the answer <span>兀r 34029h</span>
8 0
4 years ago
Answer question bellow!!!
Elina [12.6K]
The answer to your question is false
3 0
3 years ago
Alondra received a 14% hourly raise, but the number of hours worked decreased by 7.5%. If her wage was $10.50 an hour and she wo
Elodia [21]

Answer:

She will earn <u>$442.89</u> in one week after the changes.

And this is <u>more</u> than her previous weekly earnings.

Step-by-step explanation:

Given:

Alondra received a 14% hourly raise, but the number of hours worked decreased by 7.5%. If her wage was $10.50 an hour and she worked 40 hours per week before the changes.

Now, to find money she will earn in one week after the changes.

Her wage was = $10.50.

She worked per week = 40 hours.

So, her salary before changes:

10.50\times 40\\\\=\$420.

Thus, the salary per week before changes is $420.

Now, to get her salary after 14% hourly raise:

10.50+14\%\ of\ 10.50\\\\=10.50+\frac{14}{100} \times 10.50\\\\=10.50+1.47\\\\=11.97

<u>Salary after hourly raise = $11.97 per hour.</u>

Then, to get the number of hours worked decreased by 7.5%:

40-7.5\%\ of\ 40\\\\=40-\frac{7.5}{100} \times 40\\\\=40-3\\\\=37.

<u>Number of hours per week after hours of worked decreased  = 37 hours.</u>

Now, to get the salary after changes:

<em>Salary after hourly raise × number of hours per week after hours of worked decreased</em>

=11.97\times 37

=\$442.89.

<u>Salary after changes in one week = $442.89.</u>

<u><em>As, the previous salary was $420 in one week. </em></u>

<u><em>And after changes this salary is $442.89 in one week which is more than previous. </em></u>

Therefore, she will earn $442.89 in one week after the changes.

And this is more than her previous weekly earnings.

4 0
3 years ago
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