Answer: a) 
+ 
= 1
b) The distance of two foci is 85.4 feet
c) Area = 3502.67 square feet
Step-by-step explanation: a) An ellipse has the equation in the form of:
+
= 1, where a is the horizontal axis and b is the vertical axis.
For the Statuary Hall, a = 
= 48.5 and b = 
= 23, so the equation will be
+ = 1.
b) To determine the distance of the foci, we have to calculate 2c, where c is the distance between one focus and the center of the ellipse. To find c, as a, b and c create a triangle with a as hypotenuse:
= 
c = 
c = 42.7
The distance is 2c, so 2·42.7 = 85.4 feet.
The two foci are 85.4 feet apart.
c)The area of an ellipse is given by:
A = a.b.π
A = 48.5 · 23 · 3.14
A = 3502.67 ft²
The area of the floor room is 3502.67ft².
H^2 + 3.5 = 20^2
That is the formula
y=5/2x-4
Step-by-step explanation:
im pretty sure
Answer:
5 in
Step-by-step explanation:
AC = the diameter
FA = the radius
diameter=2*radius
10=2*FA
FA=10/2
FA=5 in
Well the GCF is the number that can be used to simplify, or that fits in all of your numbers for example this are all small numbers so 2 should fit in all of them 2 fits in 4 two times 2 fits in 2 one time and 2 fits in 6 three times now lets check our variable, to find the GCF of the variable first chekc if they all have the same if they don't u can't get none of taht variebles out, but if they repeat in all like the a u will take out the smallest amount out, for example the a as one in the degree of 1 the other in to the 2 degree and the last one to teh 3 degree well the smallest degree will be 1 so u will only take 1 a out so now ur GCF looks like 2a... Lets check the other variables, b is used in all of them and the smallest degree is b2 so we will take out 2 b's out so now my GCF looks like 2ab2 now lets check our last variable the, the c has the smallest degree of 1 so we will only take 1 c out
this means our final GCF is "2ab2c"
Hoep this helps
