13 + 13 + 9 + 9 = 44 feet.
Please make this answer the brainliest!
Answer:
1.38 to the nearest hundredth.
Step-by-step explanation:
Dividing:
x + 1 ) 3x - 1 ( 3
3x + 3
-4
so (3x - 1) / (x + 1) = 3 - 4 / x+ 1
Integral of (3 - 4 / x+1 ) = 3x - 4 ln(x + 1)
Between limits of 1 and 2 we have:
(3(2) - 4 ln 3) - (3 - 4 ln2)
= 1.6056 - 0.2274
= 1.3782.
m5=75 degrees
m11=75 degrees
m16=65 degrees
To find 5, realize angles 5 and 8 equal 180, because they make up a straight line, line d.
180-105=75
To find 11, it is the same as finding 7. Just look at the similar sizes. Angle 7 is the same at angle 5, just turned around. There’s a term for this pair angles that I don’t remember now but it exists. Now, lines a and b are parallel, so their angles between lines that intersect both are the same too. This means, as angle 5 equals angle 7, angle 7 equals angle 11.
To find 16, we use a combination of the methods used in finding the previous angles.
180-115=65 degrees is angle 4
Angle 4=Angle 16
Knowing the two angles given and that lines a and b are parallel, you could find the measurements of every angle in each intersection if you wanted to.
Answer:
85
Step-by-step explanation:
64+16+4+1= 85 is the total distance i believe
Answer:
The minimum number of different tanks needed to safely house all the fish is:
Step-by-step explanation:
To identify the minimum number of different tanks, we're gonna concentrate in a fish species, in this case can be the A: as you see in the table, the A species can live with all the fish excepting the F and G, by their side, the F and G can't live together , by this reason, this three species must live in a different tank, in the next form:
- Tank 1: <em>A</em>
- Tank 2: <em>F</em>
- Tank 3: <em>G</em>
Now the B species, it can live with A, F and G, but for this example we can put in the tank 1 (the tank of the A species). The C especies can live with A, F and G, but how we have A and B together, we're gonna put the C especies in the tank 3 (the tank of the G especies). The D species can live with A and G, we're gonna put in the tank 1 because can live with B species too. The E species can live with A and F, we're gonna put in the tank 2 (the tank of the F species) because the E species can't live with D that is in the in the tank 1. Al last, the H species just can live with A, E, F, and H species, by this reason, the only tank that can be put is the tank 2. In this form, the order is the next:
- Tank 1: <em>A, B, D</em>.
- Tank 2: <em>F, E, H</em>.
- Tank 3: <em>G, C</em>.
And t<u>he owner of the pet store must buy three different tanks to display these tropical fish</u>.
