Answer:
Min:3 Q:66-9 Med:9 Q3:10-14 Max19
5∧2(exponent of 2) - 1 =24
sketch the situation
a trigonometric function that is a relation between the angle of elevation and the 2 sides of the rectangles is the tan
![\tan \theta=\frac{opp}{adj}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%3D%5Cfrac%7Bopp%7D%7Badj%7D)
![\tan \theta=\frac{20}{30}=\frac{2}{3}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%3D%5Cfrac%7B20%7D%7B30%7D%3D%5Cfrac%7B2%7D%7B3%7D)
find the inverse
![\begin{gathered} \tan ^{-1}(\frac{2}{3})=\theta \\ \theta=33.69º \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctan%20%5E%7B-1%7D%28%5Cfrac%7B2%7D%7B3%7D%29%3D%5Ctheta%20%5C%5C%20%5Ctheta%3D33.69%C2%BA%20%5Cend%7Bgathered%7D)
after rounding the angle of elevation is 34º.
Hello! So, this question is in the form of ax² - bx - c. First thingd first, let's multiply a and c together. c = -8 and a = 5. -8 * 5 is -40. Now, let's find two factors that have a product of 40, but a sum of 18. If you list the factors, you see that 2 and 20 have a product of 40, but 2 - 20 is -18. The factors we will use are -2 and 20.
How to factor it:
For this question, you can use something called a box method and factor it by finding a factor of each column and row. Just make 4 boxes and put 5x² on the top left and -40 on the bottom left box. Put 2x on the top right box and -20x on the bottom left box. Now, factor out for each row and column. The factors should be 5x + 2 for the top part and x - 4 for the side. It should look like (5x + 2)(x - 4). Let's check it. Solve it by using the FOIL method and you get 5x² - 20x + 2x - 8. Combine like terms and you get 5x² - 18x - 8. There. The answer is B: (5x + 2)(x - 4)
Note: The box method may be challenging at first, but it can be really helpful on problems like these.
Answer:
With a 5-digit number, you have 5 choices for the first digit. There will be 4 digits left so you have 4 choices for the second digit. After you have chosen the first 2 digits there will be 3 remaining so you will have 3 choices for the third digit. Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 2 and 1