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3 years ago

Why is the absolute value of a number always positive?

Mathematics

2 answers:

Goshia [24]3 years ago

8 0

Because the number is positive

Snowcat [4.5K]3 years ago

7 0

It's not. The absolute value of any number is the positive version of that number except for the absolute value of 0. This is the only situation where the absolute value of a number is not positive. The absolute value of 0 is just 0.

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Solve and show your work please!x+7=2(3x-4)

Brrunno [24]

x + 7 = 2(3x - 4) Remove the brackets

x + 7 = 2*3x - 4*2

x + 7 = 6x - 8 Subtract 7 from both sides.

x + 7 - 7 = 6x - 8 - 7

x = 6x - 15 Subtract 6x from both sides

x - 6x = - 15

-5x = - 15 Divide by -5

-5x/-5 = -15/-5

x = 3

6 0

3 years ago

Why are asymptotes important in rational function graphs

leonid [27]

Answer:

when sketching the curves of functions.

Step-by-step explanation:

There is a wide range of graph that contain asymptotes and that includes rational functions, hyperbolic functions, tangent curves, and more. Asymptotes are important guides when sketching the curves of functions. This is why it’s important that we know the properties, general forms, and graphs of each of these asymptotes.

6 0

2 years ago

a jar contains 5 blue marbles and 3 red marbles. suppose you choose a marble at random and do not replace it. then choose a seco

lina2011 [118]

$\mathbb P(R_1\cap R_2)=\mathbb P(R_2\mid R_1)\mathbb P(R_1)$

The probability of drawing a red marble on the first attempt is

$\mathbb P(R_1)=\dfrac{\dbinom31}{\dbinom51}=\dfrac35$

After the first marble is drawn, and we know it to be red, we're drawing the next marble from a pool with one less marble than before (i.e. conditioning on the event $R_1$ ). So

$\mathbb P(R_2\mid R_1)=\dfrac{\dbinom21}{\dbinom71}=\dfrac27$

And so

$\mathbb P(R_1\cap R_2)=\dfrac35\cdot\dfrac27=\dfrac6{35}$

4 0

3 years ago

For which value(s) of x will the rational expression below equal zero? Check all that apply.

Ivahew [28]

Answer: D.-6 and F.3

Step-by-step explanation:

The given rational number : $\dfrac{(x-3)(x+6)}{(x+7)}$

To find : The value of x , where the rational expression becomes equal zero.

Let's check all the options :

A. 7

At x= 7 , $\dfrac{(7-3)(7+6)}{(7+7)}=\dfrac{26}{7}\neq0$

B. -7

At x= 7 , $\dfrac{(-7-3)(-7+6)}{(-7+7)}=\dfrac{10}{0}=\infty\neq0$

C. 6

At x= 6 , $\dfrac{(6-3)(6+6)}{(6+7)}=\dfrac{36}{13}\neq0$

D. -6

At x= -6 , $\dfrac{(-6-3)(-6+6)}{(-6+7)}=\dfrac{0}{1}=0$

E. -3

At x= -3 , $\dfrac{(-3-3)(-3+6)}{(-3+7)}=\dfrac{-9}{2}\neq0$

F. 3

At x= 3 , $\dfrac{(3-3)(3+6)}{(3+7)}=0$

Thus, at x= -6 and 3 , the rational expression equals to zero .

So , the correct options are : D.-6 and F.3

8 0

3 years ago

Read 2 more answers

Write a slope-intercept form of the equation if it passed the

inna [77]

Answer:

$\sf\longrightarrow \boxed{\pink{\sf 3x + 4y -8=0}}$

Step-by-step explanation:

We need to write the slope intercept form of the equation which passes through (4,-1) and parallel to the line y = -3/4x .

We know that the line parallel to a given line has the same slope . Therefore the slope of the line will be , ( on comparing to Slope Intercept Form ) .

$\sf\longrightarrow Slope =\dfrac{-3}{4}$