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Len [333]
4 years ago
6

Why is the absolute value of a number always positive?

Mathematics
2 answers:
Goshia [24]4 years ago
8 0
Because the number is positive
Snowcat [4.5K]4 years ago
7 0

It's not. The absolute value of any number is the positive version of that number except for the absolute value of 0. This is the only situation where the absolute value of a number is not positive. The absolute value of 0 is just 0.

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I need to find the measurements of the angles 1,2,3,and 4
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1)40 2) 75 3)105 4)140
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4 years ago
The number of chips of different colors in Amy's bag is shown below: 8 blue chips 9 pink chips 1 white chip Amy takes out a chip
Anastasy [175]

Answer:

1/4

Step-by-step explanation:

8 blue chips 9 pink chips 1 white chip = 18 chips

P( pink) = pink/total = 9/18 = 1/2

Replace

8 blue chips 9 pink chips 1 white chip = 18 chips

P( pink) = pink/total = 9/18 = 1/2

P(pink, replace, pink) = 1/2 * 1/2 = 1/4

3 0
4 years ago
Read 2 more answers
Go step by step to reduce the radical of the equation given. (Figure the step for the box)
Rama09 [41]

\sqrt{32} ~~ \begin{cases} 32=2\cdot 2\cdot 2\cdot 2\cdot 2\\ \qquad 2^4\cdot 2\\ \qquad 2^{(2)(2)}\cdot 2\\ \qquad (2^2)^2\cdot 2 \end{cases}\implies \sqrt{(2^2)^2\cdot 2}\implies 2^2\sqrt{2}\implies 4\sqrt{2}

7 0
2 years ago
A bunch of neighborhood kids went on a hoke through the nature center. The total mileage they walked was 16 2/3 miles. If each k
juin [17]

Answer:

\large \boxed{4}

Step-by-step explanation:

\text{No. of students} = \dfrac{\text{Total distance}}{\text{Distance per student}}

\begin{array}{rccl}16\frac{2}{3} \div4\frac{1}{6}& = & \dfrac{50}{3} \div \dfrac{25}{6} & \text{Mixed numbers to improper fractions}\\\\ & = & \dfrac{50}{3} \times \dfrac{6}{25} & \text{Inverted 2nd fraction and changed to multiply}\\\\ & = & \dfrac{2}{3}\times \dfrac{6}{1} & \text{Cancelled the 25s}\\\\ & = &\dfrac{2}{1}\times \dfrac{2}{1} & \text{Cancelled the threes}\\\\ & = &\mathbf{4} & \text{Multiplied the fractions}\\\end{array}\\\large \boxed{\textbf{Four}} \text{ students went on the trip.}

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-%20x%20-%206%20%5Cdiv%20%7Bx%7D%5E%7B2%7D%20-%204" id="TexFormula1" title="x^{2
joja [24]

\bf x^2-x-6\div x^2-4\implies \cfrac{x^2-x-6}{x^2-4}\implies \cfrac{(x-3)(x+2)}{\underset{\textit{difference of squares}}{x^2-2^2}} \\\\\\ \cfrac{(x-3)~~\begin{matrix} (x+2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{(x-2)~~\begin{matrix} (x+2) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{x-3}{x-2}

8 0
4 years ago
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