If you do in fact mean 
(as opposed to one of these being the derivative of 
at some point), then integrating twice gives
From the initial conditions, we find
Eliminating 
, we get
![C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)](https://tex.z-dn.net/?f=C_1%20%3D%20-%5Cdfrac%7B%5Cln%286%29%7D5%20%3D%20-%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%20%5Cimplies%20C_2%20%3D%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29)
Then
![\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20%3D%20%5Cln%7Cx%7C%20-%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%5C%2Cx%20%2B%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%7D)
I suppose the / are absolute value lines.... so ill answer it that way, -(-2) simplifies to 2. -/-2/ simplifies to -2
Answer:
11
Step-by-step explanation:
8 + 7 = 15.
15 - 4 = 11
Your answer would be 11.
Your answer will be 5850 30% of 4500 is 1350.
4500 + 1350 = 5850.
Answer: using the street route, he drove for half hour/0.50hr or 30minutes. Hence he covered 27miles on that trip, deducted from 54miles per hour for 0.5hr.Paid a toll fee of $1.25 which is the cost per car at the toll.
Step-by-step explanation: Choose all that apply A CH
