1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ozzi
3 years ago
14

If point P(2,-4) is reflected over the y-axis, determine the coordinates of the image

Mathematics
1 answer:
Georgia [21]3 years ago
4 0
If point P is reflected over the y-axis then the new point should be (-2, -4).
You might be interested in
PLS HELP MEE ASAP 1 MIN LEFT HELPP!!!!!!!!!
artcher [175]

Answer: BC = 5.83

Step-by-step explanation:

Luckily, the triangle is placed on the graph nicely so we can count the legs of the triangle:

AB = 5

AC = 3

BC = ?

To find BC, we can simply use the Pythagorean Theorem:

a^{2}+b^{2}=c^{2}

5^2 + 3^2 = c^2

25 + 9 = c^2

34 = c^2

Now square root to find c, or BC.

\sqrt{34}=\sqrt{c^{2} }

c = 5.83 (rounded by nearest hundredth)

4 0
3 years ago
Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event
mezya [45]

Answer:

The probability of Javier volunteers for less than three a month is 25%

Step-by-step explanation:

According to the questions,

The probability of Javier to attend exactly 5 events :-

P ( x = 5 ) = 25% = \frac{1}{4}

The probability of Javier to attend exactly 4 events :-

P ( x = 4 ) = \frac{1}{4}

The probability of Javier to attend exactly 3 events :-

P ( x = 3 ) = \frac{1}{4}

The probability of Javier to attend exactly 2 events :-

P ( x = 2 ) = \frac{3}{20}

The probability of Javier to attend exactly 1 events :-

P ( x = 1 ) = \frac{1}{20}

The probability of Javier to attend no events :-

P ( x = 0 ) = \frac{1}{20}

Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).

P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )

P ( x < 3 ) = \frac{1}{20} + \frac{1}{20} + \frac{3}{20}   = \frac{1 + 1 + 3}{20}  = \frac{5}{20}  = \frac{1}{4}   = 0.25 = 25 %.

8 0
3 years ago
Find the volume of a right circular cone that has a height of 11.8 ft and a base with a radius of 7.3 ft. Round your answer to t
lora16 [44]

Answer:

The answer to your question is 658.2 ft³

Step-by-step explanation:

Data

Volume = x

height = 11.8 ft

radius = 7.3 ft

Formula

Volume of a cone = 1/3πr²h

Process

1.- Calculate the volume

Volume = 1/3(3.14)(7.3)²(11.8)

Volume = 1/3(3.14)(7.3)²(11.8)

Volume = 1/3(3.14)(53.29)(11.8)

Volume = 1/3(1974.5)

Rounded to the nearest tenth

Volume =  658.2 ft³

3 0
3 years ago
Please help me!!<br> Best one gets brailiest!
brilliants [131]
<h3>Answer:  8 = g/3</h3>

Explanation:

When translating word problems into equations, the word "is" often means "equal sign"

The term quotient is the result of a division problem. So "quotient of g and 3" means "g divided by 3" or g/3.

5 0
3 years ago
Given f(x) = x^2-3 and g(x)=x+2/x. Find (g°f)(4)
goblinko [34]

Answer:

15/13

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • Mara had 7 cookies.She ate some Now she has 4 cookies. How many cookies did she eat? Draw a tape diagram
    6·2 answers
  • Simplify (3x − 5) − (4x + 6).
    15·1 answer
  • You need half a liter of milk how many millimeters do you need
    6·1 answer
  • What is the slope intercept form of 3x+4y=-24
    15·2 answers
  • A salesperson earns $350 per week plus 12% of her weekly sales. The expression representing her earnings is 350+0.12x. which of
    14·2 answers
  • Please help me with this
    7·1 answer
  • An isosceles, obtuse triangle has one angle with a degree measure that is 50$\%$ larger than the measure of a right angle. What
    9·1 answer
  • Find the sum of the infinite geometric series -27, -9, -3, … The ratio is /3 and u1 is -27
    12·1 answer
  • Is this a good math essay?
    15·1 answer
  • Just give the answer
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!