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scoundrel [369]
3 years ago
14

Solve the inequality 3(4-6)+ 2≥2(-t+3)+4

Mathematics
2 answers:
bearhunter [10]3 years ago
4 0

Answer:

I need the work please

Step-by-step explanation:

Papessa [141]3 years ago
3 0
The answer is t ≥ 7
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A simple random sample of 1000 American adults found that the average number of hours spent watching television during a typical
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Answer:

Larger for the sample of Canadians

Step-by-step explanation:

The larger the sample size, the smaller the standard deviation (sampling variability) associated with the sample means and vice-versa.

The sample of Canadians is smaller, it is expected that their sampling variability is larger than the sample of Canadians based on the rule that as the sample size increases, the standard deviation of the means decreases; and as the sample size decreases, the standard deviation of the sample means increases

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How do I write an explicit rule for this sequence?
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next should be 2250 if my math is correct

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If the common difference in an article is -3 and the first term is 7 what is the 14th term?
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In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
What can you divide a2b5 by to get a quotient of 1?
Kitty [74]

9514 1404 393

Answer:

  a^2b^5

Step-by-step explanation:

Anything divided by itself is 1.

That is, anything multiplied by its reciprocal is 1. This value (the reciprocal of the expression) is called the "multiplicative inverse." Its value is that the product of an expression and its multiplicative inverse is 1, the multiplicative identity element. (Anything times 1 is itself.)

So, to get 1 as a product, multiply by 1/(a^2b^5), which is to say, divide by a^2b^5 to get 1 as a quotient.

8 0
2 years ago
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