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3 years ago

11

Be helpful please !

2 answers:

AysviL [449]3 years ago

7 0

Answer:

The answer can be calculated by doing the following steps;

Step-by-step explanation:

CORRESPONDING ANGLES:

These are the angles in which one angle is interior to the first line and the second angle is exterior to the second line but both the angels lie on the same side of transversal.

kolbaska11 [484]3 years ago

3 0

Answer:

ANSWER: angle <1 = 140°

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miskamm [114]

Answer:

x = 0

Step-by-step explanation:

i) x - 11 + 1 < 15

x - 10 < 15

x < 10 + 15

x < 25

ii) x - 11 + 1 > 15

x - 10 > 15

x > 25

Therefore to compare (i) and (ii)

25 < x < 25

In any case, x = 0

4 0

3 years ago

Two mechanics worked on a car. The first mechanic worked for 5 hours, and the second mechanic worked for 15 hours. Together they

Wewaii [24]

X = rate of mechanic who worked 5 hours

y = rate of mechanic who worked 15 hours

x + y = 200
5x + 15y = 1950

you find the first variable in one of the equations, then subsitute the result into the other equation. your answer would be:

the mechanic who worked for 5 hours charged $105 per hour, the one who worked 15 hours charged $95 per hour.

hope this helps :)

3 0

3 years ago

a rectangular piece of cardboard measuring 30 inches by 20 inches is made into an open box by first cutting an identical square

lina2011 [118]

Draw a graph the function and find the value of x that produces the maximum

4 0

3 years ago

What is an equation of the line that passes through the point(2,−2) and is parallel to the line 5x-2y=4

mixer [17]

Answer:

y = 5/2x - 7

Step-by-step explanation:

5x - 2y = 4

5x - 4 = 2y

y = 5/2x - 2

Slope = 5/2

Point (2,-2)

y-intercept: -2 - (5/2)(2) = -2 - 5

= -7

3 0

2 years ago

Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

<u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
<u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
<u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

Area of square B is 144 inches²
Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

<u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

<u>Here</u><u>, </u>

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

6 0

2 years ago