With all of the following you are able to make a graph, table, and a equation.
Wht do you need help with exactly ?
Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
V = lwh
V = (x + 2)(x + 3)(x)
V = (x)(x^2 + 3x + 2x + 6)
V = (x^3 + 3x^2 + 2x^2 + 6x)
V = x^3 + 5x^2 + 6x
All you do is foil the dimensions together and then combine like terms. Hope this helps!
Answer:
x, StartFraction x Over 2 EndFraction, StartFraction x Over 4 EndFraction, StartFraction x Over 8 EndFraction, ellipsis
Step-by-step explanation:
