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Katena32 [7]
3 years ago
7

Which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring? −b, b2 − 4ac, 2a Use th

e part of the quadratic formula that you chose above and find its value given the following quadratic equation: 2x2 + 7x + 3 = 1
Mathematics
1 answer:
Korolek [52]3 years ago
3 0
It would be: b³ and 4ac. The equation containing these terms is the discriminant. The equation is b²-4ac. a, b and c are the first, second and third are the coefficients of the first, second and third terms of the quadratic equation, respectively.

Let's arrange the equation to the standard one first

2x² + 7x + 3 - 1 = 0
2x² + 7x + 2 = 0

b² - 4ac = (7)² - 4(2)(2) = 33

If the answer is a perfect square, then it can be factored. If not, like in this case, it can't be factored.
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You earn a 90% on his science test you answer 18 questions correctly how many questions were on the test
Bogdan [553]
Hello there!

The correct answer is 20.

Hope This Helps You!
Good Luck :)
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3 years ago
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The points (3, 9) and (–3, –9) are plotted on the coordinate plane using the equation y = a • x. What is the value of a? Enter y
Ilia_Sergeevich [38]

So fill out the coordinate with those given numbers, and count how far apart they are and you will get your answer. Then times it by x.

8 0
3 years ago
The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length.
emmasim [6.3K]

Step-by-step explanation:

1) The area of rectangle is ( 30x²y + 20xy ) cm² and its breadth is 10xy cm .Find its length....

= Solution ,

Length ( L ) = ?

breadth ( b ) = 10xy cm

area ( a ) = ( 30x² + 20xy )

Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

or,\frac{30 {xy + 20xy}^{2} }{10xy}  = l \\

or, \: l = 3 {x}^{2 - 1}  + 2cm

\boxed{\sf{l = (3x+2)cm}}

2) Subtract the quotient when 20x⁴y² is divided by 5x³y from the product of 2x and 3y.

= Solution,

= \frac{20 {x}^{4} {y}^{2}  }{5 {x}^{3} y}   \\

= 4xy

The product of 3x and 4y = 6xy

= 6x - 4xy

= \boxed{\sf {2xy}}

hope it helped !!!!

7 0
1 year ago
Thanks who ever helped ​
NeTakaya

Answer:

60 × 50 = 3000

7 × 50 = 350

60 × 4 = 240

7 × 4 = 28

3000 + 350 + 240 + 28 =3618

54 × 67 = 3618

3 0
2 years ago
In a beach town, 13% of the residents own boats. A random sample of 100 residents was selected. What is the probability that les
mariarad [96]

Answer:

Approximately 0.038 (or equivalently 3.8\%,) assuming that whether each resident owns boats is independent from one another.

Step-by-step explanation:

Assume that whether each resident of this town owns boats is independent from one another. It would be possible to model whether each of the n = 100 selected residents owns boats as a Bernoulli random variable: for k = \lbrace 1,\, \dots,\, 100\rbrace, X_k \sim \text{Bernoulli}(\underbrace{0.13}_{p}).

X_k = 0 means that the kth resident in this sample does not own boats. On the other hand, X_k = 1 means that this resident owns boats. Therefore, the sum (X_1 + \cdots + X_{100}) would represent the number of residents in this sample that own boats.

Each of these 100 random variables are all independent from one another. The mean of each X_k would be \mu = 0.13, whereas the variance of each X_k\! would be \sigma = p\, (1 - p) = 0.13 \times (1 - 0.13) = 0.1131.

The sample size of 100 is a rather large number. Besides, all these samples share the same probability distribution. Apply the Central Limit Theorem. By this theorem, the sum (X_1 + \cdots + X_{100}) would approximately follow a normal distribution with:

  • mean n\, \mu = 100 \times 0.13 = 13, and
  • variance \sigma\, \sqrt{n} = p\, (1 - p)\, \sqrt{n} = 0.1131 \times 10 = 1.131.

11\% of that sample of 100 residents would correspond to 11\% \times 100 = 11 residents. Calculate the z-score corresponding to a sum of 11:

\begin{aligned}z &= \frac{11 - 13}{1.131} \approx -1.77 \end{aligned}.

The question is (equivalently) asking for P( (X_1 + \cdots + X_{100}) < 11). That is equal to P(Z < -1.77). However, some z-tables list only probabilities like P(Z > z). Hence, convert P(Z < -1.77)\! to that form:

\begin{aligned} & P( (X_1 + \cdots + X_{100}) < 11) \\ &= P(Z < -1.77) \\ &= 1 - P(Z >1.77) \end{aligned}.

Look up the value of P(Z > 1.77) on a z-table:

P(Z > 1.77) \approx 0.962.

Therefore:

\begin{aligned} & P( (X_1 + \cdots + X_{100}) < 11) \\ &= 1 - P(Z >1.77) \\ &\approx 1 - 0.962 = 0.038 \end{aligned}.

4 0
3 years ago
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