Question

Suppose you increase your walking speed from 6 m/s to 11 m/s in a period of 3 s. What is your acceleration? Answer and units

Answer 1

Acceleration  of a body is defined as rate of chance in velocity with respect to time and its S.I. Units are $meter/sec^{2}$/ or $m/s^{2}$

Magnitude of average acceleration of a body = (final speed - initial speed)/time interval = $(v- u)/t$

where, final speed =v= 11 m/s; initial speed = u = 6 m/s; and time interval = t = 3 s

Hence acceleration = $(11-6)/3$ = $5/3$ = $1.67 m/s^{2}$

Answer 2

Answer:

The acceleration of the object is 1.667 m/s2.

Explanation:

Given data:

Initial velocity = v1 = 6 m/s

Final velocity = v2 = 11 m/s

Time period = t = 3 s

Solution:

Acceleration = a = ( v2 - v1)/t

By putting values in the above formula:

Acceleration = a = (11 - 6)/3

                        a = 5/3 = 1.6667

Explanation:

Acceleration of an moving object is the change of velocity of an object divided by the total time taken by the object which is time period. So by putting values it comes that acceleration of object is 1.6667 m/s2.

The unit is meter per second square.