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anyanavicka [17]
4 years ago
7

Describe the difference between an element and a compound.

Chemistry
1 answer:
n200080 [17]4 years ago
7 0

Explanation:

     An element is a distinct substance that cannot be split-up into simpler substances. Such substances consists of only one kind of atom. There are over a hundred known element that has been discovered to date. Most elements are symbolized based on some conventions.

       A compound is a substance that is formed from two or more kinds of atoms/elements joined together in a definite grouping. The properties of a compound is different from those of the individual elements that combines to make them up. Several millions of compounds are known. They are derived from the combination of elements.

How will ions combine to form compounds?

Ions are formed when an atom loses or gain electrons. This leaves them with either a net positive or negative charge on them.

Most atoms gives up their ions in order to attain a stable electronic configuration.

When two oppositely charged ions are brought close to each other, they attract one another with an electrostatic force. This attraction is what forms the bonds in making ionic/electrovalent compounds.

learn more:

Ionic compounds brainly.com/question/6071838

#learnwithBrainly

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Answer : The mass of sodium fluoride added should be 0.105 grams.

Explanation : Given,

The dissociation constant for HF = K_a=6.8\times 10^{-4}

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First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.8\times 10^{-4})

pK_a=4-\log (6.8)

pK_a=3.17

Now we have to calculate the concentration of NaF.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[NaF]}{[HF]}

Now put all the given values in this expression, we get:

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[NaF]=0.00834M

Now we have to calculate the moles of NaF.

\text{Moles of NaF}=\text{Concentration of NaF}\times \text{Volume of solution}=0.00834M\times 0.300L=0.0025mole

Now we have to calculate the mass of NaF.

\text{Mass of }NaF=\text{Moles of }NaF\times \text{Molar mass of }NaF=0.0025mole\times 42g/mole=0.105g

Therefore, the mass of sodium fluoride added should be 0.105 grams.

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