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3 years ago

N divided by 2 - 6 = 8

Mathematics

1 answer:

dybincka [34]3 years ago

7 0

Answer:

N=28 my friend

Step-by-step explanation:

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(a + 3)(a - 2) please help

gregori [183]

Final Answer: a2+a−6

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3 years ago

2+2+2+2+2+1+1+1+2+3+4+6=<br> brailiest anyone

garik1379 [7]

The Answer To <span>2+2+2+2+2+1+1+1+2+3+4+6= 28</span>

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3 years ago

Read 2 more answers

there are 15 picecs of fruit in a bowl and 6 of them are apples. what percentage of the pieces of fruit in the bowl are apples

Grace [21]

Answer:

0.06 %

Step-by-step explanation:

3 0

3 years ago

The teacher wants to make a fruit punch for the class party. She needs 30 quarts of juice. If there are 15 kids bringing in juic

SpyIntel [72]

Answer:

4 pints

Step-by-step explanation:

30 quarts ÷ 15 kids = 2 quarts per kid

there are 2 pints in a quart so..

2 quarts per kid x 2 pints per quarter = 4 pints

8 0

4 years ago

The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am

posledela

Step-by-step walkthrough:

Well a standard half-life equation looks like this.

$N = N_0 * (\frac{1}{2})^{t/p$

$N_0$ is the starting amount of parent element.

$N$ is the end amount of parent element

$t$ is the time elapsed

$p$ is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days$

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2} = 37g$

Now we just gotta do some algebra. Use the original function but this time, replace $N(t)$ with 10g and solve algebraically.

$10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}$

Take the log of both sides.

$log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})$

Use the exponent rule for log laws that, $log(b^x) = x*log(b)$

$log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})$

$\frac{log(\frac{5}{37})}{log(\frac{1}{2})} = \frac{t}{2.8days}$

$2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})} = t$

slap that in your calculator and you get

$t = 8.1 days$

7 0

2 years ago