Option C:
The solution of inequality 2x + y < 10 is (5, –3).
Solution:
Given inequality is 2x + y < 10.
Lets substitute the given points in the inequality and find the solution.
Option A: (6, –1)
2(6) + (–1) < 10
12 – 1 < 10
11 < 10
This is false because 11 > 10.
Therefore (6, –1) is not the solution of the inequality.
Option B: (1, 10)
2(1) + (10) < 10
2 + 10 < 10
12 < 10
This is false because 12 > 10.
Therefore (1, 10) is not the solution of the inequality.
Option C: (5, –3)
2(5) + (–3) < 10
10 – 3 < 10
7 < 10
This is true.
Therefore (5, –3) is the solution of the inequality.
Option D: (5, 5)
2(5) + (5) < 10
10 + 5 < 10
15 < 10
This is false because 15 > 10.
Therefore (5, 5) is not the solution of the inequality.
Hence Option C is the correct answer.
The solution of inequality 2x + y < 10 is (5, –3).
Answer:
A^-1:B^-1
Step-by-step explanation:
im not 100% sure but i think this is the right answer :)
18.03 inches
Put the dimensions into the pythagorean theorem, that will give you the answer.
Answer:
Step-by-step explanation:
given is a system of linear equations in 3 variables as
This can be represented in matrix form as
AX=B Or
![\left[\begin{array}{ccc}-1&-4&2\\1&2&-1\\1&1&-1\end{array}\right] *\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-10\\11\\14\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-4%262%5C%5C1%262%26-1%5C%5C1%261%26-1%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-10%5C%5C11%5C%5C14%5Cend%7Barray%7D%5Cright%5D)
So solution set
X would be 
|A|=-1(-1)+4(0)+2(-1)=--1
Cofactors of A are
-1 0 -1
-2 -1 -3
0 1 2
So inverse of A is
1 2 0
0 1 -1
1 3 -2
Solution set would be
x=12
y=-3
z=-5
Answer:
The answer is D 1, your welcome
