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iren2701 [21]
3 years ago
9

A web server hosting company advertises 99.999 percent guaranteed network uptime. (a) how many independent network servers would

be needed if each has 98 percent reliability? (round your answer up to the nearest whole number.) network servers (b) how many independent network servers would be needed if each has 89 percent reliability? (round your answer up to the nearest whole number.) network servers
Mathematics
1 answer:
larisa [96]3 years ago
3 0
<span>Instead of thinking about reliability think of failure. 99.999% reliability =0.00001 chance of failure. And 95% reliability =0.05 chance of failure. Assuming failures are independent (they probably are not) the chance of n servers failing is (0.05)n Find n such that (0.05)n=(0.00001) now do it for (0.14)n=(0.00001)</span>
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Leslie went out for a jog. When she returned she went to the tap and filled up her 500 mL reusable water bottle. She drank 250 m
Anastasy [175]

Answer:

Please find attached the required graph and

Step-by-step explanation:

The values for the information given can be written down as follows;

Time, seconds             Volume mL

0,                                    500

12,                                   450

24,                                  400

36,                                  350

48,                                  300

60,                                  250

72 250

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96 250

108 250

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168 250

180 250

192 250

204 250

216 250

228 250

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264 250

276 250

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324,                                        200

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360,                                         125

372,                                         100

384,                                         75

396,                                        50

408,                                        25

420,                                        0

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3 years ago
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Aleksandr-060686 [28]
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5 0
3 years ago
Read 2 more answers
How would I do this problem?
kenny6666 [7]

If it's a geometric sequence then:

a_1=27;\ a_2=27\\\\r=\dfrac{a_2}{a_1}\to r=\dfrac{27}{36}=\dfrac{3}{4}=0.75\\\\a_{n+1}=a_nr\\\\a_3=27\cdot0.75=20.25\ CORRECT

We calculate the fourth and fifth term of the sequence:

a_4=a_3r\to a_4=20.25\cdot0.75=15.1875\\\\a_5=a_4r\to a_5=15.1875\cdot0.75=11.390625

Answer:

In year 4 15.1875 animals.

In year 5 11.390625 animals.

7 0
3 years ago
Simplify. cos^2[(pi/2) - x] + cos^2[(pi/2) - x] + cos^2x
Ipatiy [6.2K]

Numerator
<span><span>cos<span>(<span>π/2</span>−x)</span></span>=<span>cos<span>(<span>π/2</span>)</span></span><span>cosx</span>+<span>sin<span>(<span>π/2</span>)</span></span><span>sinx</span></span>

now <span><span>cos<span>(<span>π/2</span>)</span></span>=0 and <span>sin<span>(<span>π/2</span>)</span></span>=1</span>

simplifies to : 0 + sinx = sinx

Denominator

<span><span>sin<span>(<span>π/2</span>−x)</span></span>=<span>sin<span>(<span>π/2</span>)</span></span><span>cosx</span>+<span>cos<span>(<span>π/2</span>)</span></span><span>sinx</span></span>

simplifies to : cosx + 0 = cosx

<span>⇒<span><span>cos<span>(<span>π/2</span>−x)</span></span><span>sin<span>(<span>π/2</span>−x)</span></span></span>=<span><span>sinx/</span><span>cosx</span></span>=<span>tan<span>x</span></span></span>

5 0
3 years ago
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salantis [7]

Answer:

itsa 1200 B

Step-by-step explanation:

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