niAnswer:
(A) Vx = -9.14ωCosωt,
Vy = 9.14ωSinωt
(B) ax =9.14ω²Sinωt,
ay = 9.14ω²Cosωt
Explanation:
The velocity of a body ia the time derivative of the poaition function of the body with respect to time. Given equations x = −9.14 sin ωt and y = 4.00 − 9.14 cos ωt,
All we need to do to get the velocity is to differentiate each of the equation above with respect to time in order to get Vx and Vy required of us.
Vx = dx/dt = -9.14ωCosωt and
Vy = dy/dt = 9.14ωSinωt
In order to get the acceleration we differentiate the velocity function with respect to time. That is,
A = dv/dt
ax = dVx/dt = 9.14ω²Sinωt
ay = dVx/dt = 9.14ω²Cosωt
That statement is False.
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hope this helps
Answer:
v = (2.71î + 1.24j) m/s
Magnitude of v = 2.98 m/s
Direction of v = 24.6°
Explanation:
Let the final velocity of the composite of both objects after collision be v.
According to Newton's second law of motion, in collisions, momentum is normally conserved
Momentum before collision = Momentum after collision
Momentum of object 1 before collision = (3.02)(4.63î) = (13.9826 î) kgm/s
Momentum of object 2 before collision = (2.14)(2.99j) = (6.3986 j) kgm/s
Momentum of both objects after collision = (3.02 + 2.14)(v) = 5.16v
Momentum balance
(13.9826î + 6.3986j) = 5.16v
v = (2.71î + 1.24j) m/s
Magnitide = √(2.71² + 1.24²)
Magnitude of v = 2.98 m/s
Direction of v = tan⁻¹ (1.24/2.71)
Direction of v = 24.6°
Hope this Helps!!!
Answer: Option A
Explanation