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densk [106]
3 years ago
9

Consider an electron and a proton separated by a distance of 4.5 nm. (a) what is the magnitude of the gravitational force betwee

n them? 5.1128e-20 incorrect: your answer is incorrect. n (b) what is the magnitude of the electric force between them?
Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0
A.) For letter a, we use the law of universal gravitation using the constant G = 6.674×10−<span>11 m3</span>⋅kg−1⋅s−<span>2

Grav. F = G*m1*m2*(1/d^2)

m1 is mass of electron = </span>9.11 × 10-31<span> kg
m2 is mass of proton = </span>1.67 × 10<span>-27 kg
d = 4.5 nm = 4.5 x 10^-9 m

Grav F = 5.01 x 10^-51 N

b.) </span>For letter b, we use the Coulomb's using the constant k = 9×10^9 N

Electric force = k*Q1*Q2*(1/d^2)
Q1 is charge of electron = -1.6 × 10-19 C
Q2 is charge of proton = +1.6 × 10-19 C

Electric force = 1.14 x 10^-11 N
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Answer:

200N appox

Explanation:

Step one:

Given data

mass of ball= 0.143kg

initial velocity of ball u= 42m/s

final velocity of the ball= 49m/s

time of impact= 0.005s

Step two

From the relation Ft=mΔv

we can find the average force as

F=mΔv/t

substitute

F=0.143*(49-42)/0.005

F=0.143*7/0.005

F=1.001/0.005

F=200.2

F= 200N appox

The average force is  200N

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3 years ago
Work is being done in which of these situations? All motions are at a constant velocity (including velocity = zero).
Black_prince [1.1K]
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3 years ago
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A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnet
Amanda [17]

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance R= 10\Omega

We need to calculate the  speed of the wire

Using formula of emf

\epsilon=Bvl

Using formula of current

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Put the value of \epsilon into the formula of current

I=\dfrac{Bvl}{R}

v=\dfrac{IR}{Bl}

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3 years ago
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