A toy airplane is flying at a speed of 6 m/s with an acceleration of 0.3 m/s2.
1 answer:
The final velocity of the airplane is 7.2 m/s
Explanation:
The motion of the airplane is a uniformly accelerated motion, (constant acceleration), therefore we can use the suvat equation
v = u + at
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
In this problem, we have
u = 6 m/s is the initial velocity
is the acceleration
t = 4 s is the time elapsed
Substituting the values, we find the velocity after 4 seconds:
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Answer:
M2 = 278.06 kg
Explanation:
We calculate the weight of M1
W=m*g
Where
m: mass (kg)
g: acceleration due to gravity (m/s²)
W₁=288* 9.8= 2822.4 N
Look at the attached graphic
We calculate the x-y components of the weight :
W₁x= 2822.4*sin41° N =1851.66 N
W₁y= 2822.4 *cos41° N = 2130.09 N
We apply Newton's first law for the balance in M1:
Σ Fy=0
Fn-W₁y=0 , Fn: normal force
Fn=W₁y=2130.09N
Friction Force = Ff=μs *Fn = 0.41*2130.09 =873.34 N
Σ Fx=0
T- W₁x- Ff=0
T= 1851.66 + 873.34
T= 1851.66 + 873.34
T=2725 N
We apply Newton's first law for the balance in M2:
Σ Fy=0
T- W₂ =0
W₂ = T = 2725 N
W₂ = M2*g
M2 = W₂/g
M2 = 2725/9.8
M2 = 278.06 kg
Answer:
285.7s
Explanation:
Given parameters:
Speed of the person = 1.4m/s
Unknown:
Time it takes to walk one time round the track = ?
Solution:
The circumference of the track is 400m for a standard pitch.
Now;
Speed =
Time =
Now insert the parameters;
Time = = 285.7s