1) Data:
Vo = 20 m/s
α = 37°
Yo = 0
Y = 3m
2) Questions: V at Y = 3m and X at Y = 3 m
3) Calculate components of the initial velocity
Vox = Vo * cos(37°) = 15.97 m/s
Voy = Vo * sin(37°) = 12.04 m/s
4) Formulas
Vx = constant = 15.97 m/s
X = Vx * t
Vy = Voy - g*t
Y = Yo + Voy * t - g (t^2) / 2
5) Calculate t when Y = 3m (first time)
Use g ≈ 9.8 m/s^2
3 = 12.04 * t - 4.9 t^2
=> 4.9 t^2 - 12.04t + 3 = 0
Use the quadratic equation to solve the equation
=> t = 0.28 s and t = 2.18s
First time => t = 0.28 s.
6) Calculate Vy when t = 0.28 s
Vy = 12.04 m/s - 9.8 * 0.28s = 9.3 m/s
7) Calculate V:
V = √ [ (Vx)^2 + (Vy)^2 ] = √[ (15.97m/s)^2 + (9.30 m/s)^2 ] = 18.48 m/s
tan(β) = Vy/Vx = 9.30 / 15.97 ≈ 0.582 => β ≈ arctan(0.582) ≈ 30°
Answer: V ≈ 18.5 m/s, with angle ≈ 30°
8) Calculate X at t = 0.28s
X = Vx * t = 15.97 m/s * 0.28s = 4,47m ≈ 4,5m
Answer: X ≈ 4,5 m
Answer:
Ultrasound is used by bats to navigate (move) and catch prey. Ultrasonic squeaks are produced by bats. These squeaks ponder prey and then return to the bat's ear. This provides bats with information about the location of prey, allowing them to catch it.
Explanation:
We know that acceleration due to gravity is the same for all objects. But if we drop a flower petal and a hammer from the same height, the hammer falls faster. Why does this happen?
Let me try to explain. The petal falls slower as the resistance it faces by air slows it down much more. Even though the hammer is also affected by this resistance, the speed decrease is negligible due to its weight.
To simplify, a petal is much lighter than a hammer. Even though gravity accelerates them at the same speeds, the petal slows down due to air resistance but the hammer doesn't, as its weight counteracts the air resistance.
I may be confusing at times, so please ask me if you want anything clarified :)
Hope this helps you!
Answer:
Explanation:
We would most likely write the velocity of the ball as follow :
V(b<em>all</em> with respect to t<em>rain)</em> = Vbt
