3629 you can use the digits twice make the largest four digit number

It takes Ben 2 days to write reports, and it takes Kate 3 days to write reports. Bens rate, in reports per day, is how much grea

sergejj [24]

Answer:

Ben's rate is $\dfrac{1}{6}$ greater than Kate's rate.

Step-by-step explanation:

1. If it takes Ben 2 days to write reports, then his rate is $\dfrac{1}{2}$ of reports per day.

2. If it takes Kate 3 days to write reports, then her rate is $\dfrac{1}{3}$ of reports per day.

3. Ben's rate is

$\dfrac{1}{2}-\dfrac{1}{3}=\dfrac{3-2}{6}=\dfrac{1}{6}$

greater than Kate's rate.

4 0

3 years ago

Which sentence matches the mathematical equation? p-0.40p=0.60p

IRISSAK [1]

P-0.40p = 0.60p

C. Decrease by 40% is the same as multiply by 60%.

Assume that p = 10

10 - 0.40(10) = 0.60(10)
10 - 4 = 6
6 = 6

Based on the above assumption. 40% of 10 is 4 ; and 60% of 10 is 6. So, 10 less 4(40% of 10) is equal to 6 (60% of 10).

Percentage is used because 0.40 and 0.60 will be multiplied with 100% to get the equivalent percentage 0.40 x 100% = 40% ; 0.60 x 100% = 60%

7 0

3 years ago

(Please answer! You will get brainliest, and over 100+ points..)

irakobra [83]

11 quarters and 18 dimes

Hope this helps! :D

8 0

3 years ago

Read 2 more answers

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

So

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$