Answer:
The correct answer is option d. "Its conformation will change when both an ion and a small molecule bind to it".
Explanation:
The secondary active transport is a form of active transport at which a ion (typically Na+ or H+) is transferred down its electrochemical gradient to the uphill movement of another molecule. Secondary active transport takes place by the conjunctive work of membrane-bound proteins and sodium–potassium pumps. During secondary active transport, both of these proteins change its conformation when an ion and a small molecule bind to it. This change in conformation makes possible that the ions and the small molecules pass through the membrane.
Answer:
12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).
Explanation:
The best example that illustrates a sensitive period is
letter b, where the child tries to learn in speaking a second language because
this is considered to be a sensitive period in which is the period for a
development of new opportunities that a child could learn in which learning to
speak a second language is considered to be a sensitive period.
<u>Primary structure of the protein </u>can be determined With the knowledge of the nucleotide sequence of a gene.
- Strings of amino acids make up proteins, and strings of nucleotides make up nucleic acids.
- A water molecule is removed during a biological process that links the carboxyl group of one amino acid to the amino group of a nearby amino acid to generate peptide bonds.
- The main structure of a protein is thought to be its linear amino acid sequence.
- A codon is a cluster of three mRNA nucleotides that codes for a particular amino acid.
- Each mRNA produces a protein that has a specific amino acid sequence corresponding to it. The start and stop of translation are indicated by two codons known as start and stop codons.
learn more about nucleotide here: brainly.com/question/16099437
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Answer:
See the answer below
Explanation:
1. The data from the experiment shows that <u>as the percentage of salt in the solution used to water the plants increased, the growth rate of the plants decreased</u>. As the percentage increased from A to D, the change between the average initial and the final heights decreased, meaning that an increase in the percentage of the salt in the solution used to water the plants had a negative impact on the growth rates of the plants.
2. Due to the solutions used to water the plants in groups E and F being more concentrated (hypertonic) to that of the cell sap of the plant, <u>water molecules diffused out of the cell sap to the ambient solution</u>. As time goes by, the plants lose too much water, become wilted, and died off eventually. Instead of water molecules to keep diffusing into the plants in order for them to grow, the reverse was occurring and this led to their death.
