Answer:
21. The slope is 50.
22. 0
23. y=50x
24. $2600
Step-by-step explanation:
21. The slope of the line is 50. Slope is defined as "rise over run". As the line increases, each segment moves up the y-axis by $50, and to the right on the x-axis 1 segment. (Work: 50 divided by 1)
22. The y-intercept is (0, 0), or simply 0. If you look at the graph you can see that the line crosses the y-axis at the origin. This makes the y-intercept equal to 0.
23. The slope tells you that the student makes $50 every week. The y-intercept is 0. Using the formula y=mx+b, an appropriate equation would be y=50x.
24. The equation found in problem 23 can me used to determine how much a student makes (y) after "x" weeks. Substitute 52 for x to solve for y. This becomes y=50(52). This can be simplified to y=2600. This means that after 52 weeks, the student will have made $2,600.
Answer:
Step-by-step explanation:
10 = r²h
(2r)²(2h) = 16r²h
volume of B is 1.6 times the volume of A
Answer:
C) 1/6
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this question:
We have 8 + 10 + 4 + 2 = 24 coins
Of those, 4 are nickels. So
The correct option is given by option C.
Answer: line CD (fourth choice)
====================================================
Let's go through the choices one by one
1) Segment AB is a radius, which is not a secant line. We can rule this out.
2) line DE is a tangent line which only touches the circle at exactly one spot. We need something that cuts the circle in 2 spots for it to be a secant line. This can also be crossed off the list.
3) segment HG is a chord, which is fairly close to a secant line, but it must extend infinitely in both directions. In other words, it needs to be a line instead of a line segment. This is crossed off the list.
4) line CD is a secant line. It is a geometric line in that it goes on forever in both directions (it's not a segment, and not a ray either). Also, this line crosses the circle at 2 points, which contrasts it from a tangent line. This is the answer we want.
<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
