All categories

3 years ago

What equation is equivalent to 3(a+4)-5(a-2)=22?

Mathematics

2 answers:

Nata [24]3 years ago

7 0

Answer:

a = 0

Step-by-step explanation:

=> 3(a+4)-5(a-2) = 22

Opening Brackets

=> 3a+12-5a+10 = 22

=> 3a-5a+12+10 = 22

=> -2a+22 = 22

Subtracting 22 to both sides

=> -2a = 0

Dividing both sides by -2

We get,

=> a = 0

Anna11 [10]3 years ago

6 0

Answer:

a = 0

Step-by-step explanation:

3(a+4)-5(a-2)=22

3a+12-5a+10=22

-2a+22=22

Subtract 22 from both sides

-2a=0

Multiply both sides by -1

2a= -0

2a=0

Divide both sides by 2

a=0

Hey I just realized my answer is really similar to Ujalakhan01's so sorry if it seems like I copied them.

You might be interested in

I need answer Immediately pls!!!!!!

Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

$n(U)=27$

$n(A)=7$

$n(B)=18$

$n(A'\cap B')=7$

We know that,

$n(A\cup B)=n(U)-n(A'\cap B')$

$n(A\cup B)=27-7$

$n(A\cup B)=20$

Now,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=7+18-n(A\cap B)$

$n(A\cap B)=7+18-20$

$n(A\cap B)=25-20$

$n(A\cap B)=5$

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

$\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}$

$\text{Probability}=\dfrac{5}{27}$

Therefore, the required probability is $\dfrac{5}{27}$ .

3 0

3 years ago

Find the exact value of csc² 30° + cos² 45°.

natulia [17]

$\large \underline{ \mathbb{QUESTION:}}$

Find the exact value of csc² 30° + cos² 45°.

$\large \underline{ \mathbb{SOLUTION:}}$

$\tt{csc^{2} \: 30^{o} \: + \: cos^{2} \: 45^{o} \: = \: 2^{2} \: + \: ( \frac{1}{ \sqrt{2} }^{2}) }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{ = \: 4 \: + \: \frac{1}{2} }$

$\:\:\:\:\:\:\:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt{ \red{ = \: 4 \frac{1}{2} }}}$