Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
Answer:
380
Step-by-step explanation:
Answer:
1 = 39 degrees (some theorem, like triangles sharing a bisector or something sorry)
3 = 51 degrees (if 1=39 and 2=90 degrees since its on a right angle, and a triangle's angles add up to 180, then you subtract 1 and 2 from 180 and get 51
We have that
case 1) 2x3 + 4x -----------> <span>C. cubic binomial
</span>The degree of the polynomial is 3----> <span>the greater exponent is elevated to 3
</span>the number of terms is 2
<span>
case 2) </span>3x 5 + 3x 4 + x 3--------> <span>A. Quintic trinomial
</span>The degree of the polynomial is 5----> the greater exponent is elevated to 5
the number of terms is 3
<span>
case 3) </span>x 2 + 3----------> <span>B. quadratic binomial
</span>The degree of the polynomial is 2----> the greater exponent is elevated to 2
the number of terms is 2
<span>
case 4) </span>2x 2 + x − 5 A------------> D. quadratic trinomial
The degree of the polynomial is 2----> the greater exponent is elevated to 2
the number of terms is 3
Communitive Property of Addition
