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liq [111]
3 years ago
7

Solve: 3(-x+2) < 15 A X>7 B x < 3 C x<-> D x>-3

Mathematics
1 answer:
sukhopar [10]3 years ago
7 0

Answer:

D x>-3

Step-by-step explanation:

3(-x+2) < 15

-3x + 6< 15 (Subtract 6 from both sides)

-3x < 9 (Divide 3 on both sides)

x>-3 (Flip the inequality because the variable was negative)

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Prove 2√(x) + 1/√(x + 1) &lt;= 2√(x+1) for all x in [0,inf)
EleoNora [17]
Start by multiplying each side of the inequality by \sqrt{x + 1} and simplifying:

2 \sqrt x + \frac{1}{\sqrt{x+1}}  \leq  2 \sqrt{x + 1}
(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})
2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
2 \sqrt{x^2 + x} + 1 \leq 2x + 2
2 \sqrt{x^2 + x} \leq 2x + 1
\sqrt{x^2 + x} \leq x + \frac{1}{2}

From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
x^2 + x \leq x^2 + x + \frac{1}{4}
0  \leq \frac{1}{4}, which is always true.
3 0
3 years ago
PLSSS HELP IF YOU TURLY KNOW THISS
sergey [27]
75 , if the bottom number is 4 quarters how many is 3 ?
3 0
3 years ago
Read 2 more answers
Someone knows it, I take help
Nezavi [6.7K]

Answer:

5a^2 + 7a

Step-by-step explanation:

Combine like terms

6 0
3 years ago
Which of the functions graphed below has a removable discontinuity?<br> A<br> B<br> C<br> D
PtichkaEL [24]
<h2>Answer with explanation:</h2>

We know that a removable discontinuity occurs when:

The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.

Also it is a  point on the graph such that it is undefined at that point.

The graph that has a removable discontinuity is attached to the answer.

Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.

5 0
3 years ago
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A person invests $1,150 in an account that earns 5% annual interest compounded continuously. Find when the value of the investme
AfilCa [17]

Answer:

11.1 years

Step-by-step explanation:

The formula for interest compounding continuously is:

A(t)=Pe^{rt}

Where A(t) is the amount after the compounding, P is the initial deposit, r is the interest rate in decimal form, and t is the time in years.  Filling in what we have looks like this:

2000=1150e^{{.05t}

We will simplify this first a bit by dividing 2000 by 1150 to get

1.739130435=e^{.05t}

To get that t out the exponential position it is currently in we have to take the natural log of both sides.  Since a natural log has a base of e, taking the natual log of e cancels both of them out.  They "undo" each other, for lack of a better way to explain it.  That leaves us with

ln(1.739130435)=.05t

Taking the natural log of that decimal on our calculator gives us

.5533852383=.05t

Now divide both sides by .05 to get t = 11.06770477 which rounds to 11.1 years.

7 0
3 years ago
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