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Nostrana [21]
3 years ago
10

What is the range of the following data 7, 5, 9, 10, 1, 2, 2, 8 ​

Mathematics
2 answers:
Taya2010 [7]3 years ago
7 0

Answer:

9

Step-by-step explanation:

Range is the difference between the smallest number and largest number. In this case, the smallest number is 1, and the largest is 10.

So subtract 10 and 1, which is 9.

So, the answer is 9.

eduard3 years ago
5 0

Answer:

9

Step-by-step explanation:

The range is the biggest number minus the smallest number

The biggest number in this set is 10

The smallest number is 1

10-1=

9

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10t = 90 <br><br> i seriously dont know what to put to make it longer anymore bruv
kondor19780726 [428]

Answer:t= 9

Step-by-step explanation: 10t =90

                                           divide 10 on both sides

                                            so 10t /10 and 90/10

                                             which means t=9

8 0
3 years ago
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Novosadov [1.4K]

Answer:

Step-by-step explanation

7 0
3 years ago
Why is water not used as a solvent in paper chromatography​
Anastaziya [24]

Answer:

Because the kind of compounfds that you try to determine using paper chromatography (organic compounds) are usually not soluble in water. Furthermore, water could react chemically with some of this compounds, because it's a very reactive molecule. You need organic solvents that are mostly inert.

8 0
3 years ago
6 1⁄3 + 7 1⁄4 – 2 1⁄2 =
Korvikt [17]

Answer:

11 1/12

Step-by-step explanation:

6 1/3 = 19/3

7 1/4 = 29/4

2 1/2 = 5/2

19/3 + 29/4 - 5/2


We must find the LCM of 3, 4, and 2. This happens to be 12

3*4 = 12

4*3 = 12

2*6 = 12

Multiply each fraction by the factor that'll get it to 12.


19/3 * 4/4 = 76/12

29/4 * 3/3 = 87/12

5/2 * 6/6 = 30/12

Now go through the problem


76/12 + 87/12 - 30/12

76 + 87 = 163

163/12 - 30/12

163 - 30 = 133

133/12

Simplify

133/12 = 11.0833... or 11 1/12


Hope this helps.

6 0
3 years ago
I need someone to answer asap
algol [13]

Answer:

y = 8.5

Step-by-step explanation:

7 0
3 years ago
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