What you did is set πr² equal to A then divide the π by both sides so it will cancel on the right side and keep A over π then square root r to cancel the exponent of 2
AREA OF SQUARE = SIDE * SIDE
==> (X-3)*(X-3) = (X-3)² = X²-6X+9 UNITS²
First rewrite the problem so you get
Then rewrite as
any root of 1 is one so
1/<em></em>
1/
Pull terms out from under the radical, assuming positive real numbers.
1
/2
<h2>so answer is 1/2</h2><h3>hope this helps</h3>
Answer:
-14
Step-by-step explanation:
3x/7+8=2
3x/7=2-8
3x/7=-6
3x=7(-6)
3x=-42
x=-14