1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Firdavs [7]
3 years ago
14

A rectangle is 4 times as long as it is wide. The perimeter of a rectangle is 50 cm. What are the dimensions of the rectangle?

Mathematics
2 answers:
marissa [1.9K]3 years ago
7 0
We use the equation 2x+8x=50.

10x=50
x=5

The rectangle will be 20 cm long and 5 cm wide.

Hope this helps!
Contact [7]3 years ago
4 0

Answer:

5 cm ( width ) , 20 cm (length)

Step-by-step explanation:

Let width = w

Let length = 4w

Perimeter = 50

Perimeter formula for a rectangle = 2l + 2w

Plug in the variables (width and length)

2(w) + 2(4w) = 50

2w + 8w = 50

10w = 50

w = 5

<u>Remember, recall that length = 4w</u>

length = 4w

length = 4(5)

length = 20

Therefore, the dimensions of the rectangle are 5 by 20 cm

<h3><em>If this helped you, please make sure to give me the brainliest answer to support me. It will be greatly appreciated. Thank you!</em></h3>

You might be interested in
Help me with this question please ? and how do I get the answer?
melamori03 [73]
1) you have to find the difference between pipe A and pipe B, which is 6.40.

23.55-17.15=6.40

2) after finding the difference. You will take that difference and put it out of 23.55 and multiply by 100 to get your percentage. As so:

(6.40/23.55)(100)= 27.176% which rounds to 27% as a whole number.

Your answer is 27%. Hope that helps!
7 0
3 years ago
A washing machine is filling up with water at a constant rate. The rate is Three-fourths of a gallon in StartFraction 1 over 5 E
konstantin123 [22]

Answer:

3/4 in 1/5 of 60 sec

1/5*60=12

3/4 in 12 seconds

3/4*5=15/4=3 3/4

He multiplied 3/4 by 1/5 instead of by its reciprocal , 5.

12/4=3

3 mph

3 0
3 years ago
Read 2 more answers
Find the value of sec(theta°)cos(theta°) for the following values of theta. <br> b. theta = 225
Nesterboy [21]

Answer:

sec(theta°)cos(theta°) = 1  

Step-by-step explanation:

given data

(theta°) = 225

to find out

sec(theta°)cos(theta°)

solution

as we know that given equation

(theta°) = 225

cos(theta°) will be

cos(225°) = -0.7071      .................................1

so we know

sec(theta°) = \frac{1}{cos(theta)}      ..............2

so put here value of cos(theta°)

sec(theta°) = \frac{1}{-0.7071}

sec(theta°) = - 1.4142

so

sec(theta°)cos(theta°) = -0.7071  × ( - 1.4142 )

sec(theta°)cos(theta°) = 1

so answer is sec(theta°)cos(theta°) = 1  

8 0
4 years ago
Work out the volume of a prism with an area of 10m squared and a length of 8m
Jobisdone [24]
Is it 80 m I think that’s the answer
4 0
3 years ago
How to add 4/12 and 1 2/3
kolbaska11 [484]

Answer:

1 3/5

Step-by-step explanation: First you have to line the fractions up then you add what is under the 1 which is nothing then you add 2 and 4 and get 6 then you add 12 and 3 and get 15 then it can be simplified then you get 1 3/5

3 0
3 years ago
Read 2 more answers
Other questions:
  • Critical thinking. Make a conjecture about the relationship between three consecutive whole numbers based on this relationship i
    13·1 answer
  • Solve this system of equation:<br> 5x + 2y = -15<br> 2x - 2y =-6
    14·1 answer
  • The reciprocal of a fraction less than 1 is always a fraction greater than 1.why is this?
    15·1 answer
  • There is two boxes to fill out
    6·1 answer
  • A gumball machine contains 23 Green gumballs 52 red gum balls 34 blue gum balls 61 yellow gumballs and 30 pink gumballs what per
    12·1 answer
  • 5(-10)-8(-10+1)&gt;16 steps of solving
    15·1 answer
  • Please help sbdbdbdbdbdbdndbndbbdbdbdbdb
    6·1 answer
  • What is the apparent range of the function of x shown?
    8·1 answer
  • 5+4+3=2, 6+4+3=2, 3+6+1=2, 1+2+3=2, 1+4+3=2
    13·1 answer
  • Need math help asap!
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!