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snow_tiger [21]
1 year ago
6

2 1 point Find UV. U V 56 45 --D W

Mathematics
1 answer:
Tomtit [17]1 year ago
5 0

Answer:

11

Step-by-step explanation:

UV=UW-VW=56-45=11

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a dance team has 80 dancers.The ratio of seventh-grade dancers to all dancers is 5:16.Find the number of seventh-grade dancers o
PSYCHO15rus [73]

Answer:

  25

Step-by-step explanation:

Each of the 16 "ratio units" representing all 80 dancers must stand for ...

  (80 dancers)/(16) = 5 dancers

Then 5 "ratio units" representing seventh-grade dancers will stand for ...

  5 × 5 dancers = 25 dancers

___

Another way to figure this is to write the proportion ...

  (seventh-grade dancers)/(all dancers) = 5/16

  seventh-grade dancers = (all dancers)×(5/16) = 80×5/16

  seventh-grade dancers = 25

5 0
3 years ago
In a right triangle, the acute angles measure x + 15 and 2x degrees.
Valentin [98]

Answer:

50°

Step-by-step explanation:

x+15+2x=90

3x=90-15=75

x=75/3=25

one acute angle=25+15=40°

other acute angle=2×25=50°

7 0
3 years ago
A jar contains 8 4/9 pounds of jam. If Sam eats 3 2/5 pounds of the jam, how many pounds of jam remains in the jar?
zepelin [54]
\bf 8\frac{4}{9}\implies \cfrac{8\cdot 9+4}{9}\implies \cfrac{76}{9}
\\\\\\
3\frac{2}{5}\implies \cfrac{3\cdot 5+2}{5}\implies \cfrac{17}{5}\\\\
-------------------------------\\\\
\cfrac{76}{9}-\cfrac{17}{5}\impliedby \textit{let's use an LCD of 45}\implies \cfrac{5\cdot 76-9\cdot 17}{45}
\\\\\\
\cfrac{380-153}{45}\implies \cfrac{227}{45}\implies \boxed{5\frac{2}{45}}
\\\\\\
5\frac{2}{45}\implies \cfrac{5\cdot 45+2}{45}\implies \cfrac{227}{45}
5 0
3 years ago
The sum of a number times 6 and 5 equals 4 translate the sentence into an equation
yan [13]
If x is the number we get:-

6x + 5 = 4
3 0
3 years ago
Solve the system.
svetoff [14.1K]

Answer:

(0, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y + 5x = 1

5y - x = 5

<u>Step 2: Rewrite Systems</u>

y + 5x = 1

  1. Subtract 5x on both sides:                    y = 1 - 5x

<u>Step 3: Redefine Systems</u>

y = 1 - 5x

5y - x = 5

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitution in <em>y</em>:                      5(1 - 5x) - x = 5
  2. Distribute 5:                             5 - 25x - x = 5
  3. Combine like terms:                5 - 26x = 5
  4. Isolate <em>x</em> term:                          -26x = 0
  5. Isolate <em>x</em>:                                   x = 0

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define equation:                    5y - x = 5
  2. Substitute in <em>x</em>:                       5y - 0 = 5
  3. Subtract:                                 5y = 5
  4. Isolate <em>y</em>:                                 y = 1
8 0
2 years ago
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