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ella [17]
3 years ago
5

Can someone please explain to me how the points work when you ask a question? Worth 30 points I think, I still don't know how th

e points work, so please help me out
Computers and Technology
2 answers:
12345 [234]3 years ago
6 0

Answer: Points Are For Asking Queston Incase You Ever get A Hard Queston

ale4655 [162]3 years ago
4 0

Answer:

just ask a question and you can select how much points you wanna select and half of it will go to the person.

Explanation:

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Write a program that uses the Purchase class in 5.13. Set the prices to the following: Oranges: 10 for $2.99 Eggs: 12 for $1.69
Xelga [282]

Answer:

Explanation:

The following program is written in Java. Using the program code from Purchase class in 5.13 I created each one of the fruit objects. Then I set the price for each object using the setPrice method. Then I set the number of each fruit that I intended on buying with the setNumberBought method. Finally, I called each objects getTotalCost method to get the final price of each object which was all added to the totalCost instance variable. This instance variable was printed as the total cost of the bill at the end of the program. My code HIGHLIGHTED BELOW

//Entire code is in text file attached below.

//MY CODE HERE

       DecimalFormat df = new DecimalFormat("0.00");

       oranges.setPrice(10, 2.99);

       oranges.setNumberBought(2*12);

       eggs.setPrice(12, 1.69);

       eggs.setNumberBought(2*12);

       apples.setPrice(3, 1);

       apples.setNumberBought(20);

       watermelons.setPrice(1, 4.39);

       watermelons.setNumberBought(2);

       bagels.setPrice(6, 3.50);

       bagels.setNumberBought(12);

       totalCost = oranges.getTotalCost() + eggs.getTotalCost() + apples.getTotalCost() + watermelons.getTotalCost() + bagels.getTotalCost();

       System.out.println("Total Cost: $" + df.format(totalCost));

   }

}

5 0
3 years ago
Help me please, I'm attempting a test<br>​
dusya [7]
It’s A it’s a keyboard
8 0
3 years ago
Read 2 more answers
You can use a(n) ______________to store large amounts of customer data for a website.
BaLLatris [955]

You can use a(n) <u>database server; Databases, like MySQL</u><u> and PostgresSQL, are widely used to store data.</u>to store large amounts of customer data for a website.

<h3>What is the difference between POP3 and IMAP coursera?</h3>

POP3 can only download email to one local device. IMAP can only download email to one local device. POP3 is used for sending emails. IMAP can download emails onto multiple devices.

<h3>When would you use IMAP?</h3>

IMAP and POP are two methods to access email. IMAP is the recommended method when you need to check your emails from several different devices, such as a phone, laptop, and tablet.

To learn more about database server, refer

brainly.com/question/23752341

#SPJ4

5 0
2 years ago
How to get an object from a container in java.
Vinil7 [7]
If it stores any type of objects mixed, use Object as storage class. All classes inherit from Object and for primitives use their respective wrapper classes. Or just use one of the bazillion container classes that already exist.
3 0
3 years ago
The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices
erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;  

import java.util.Arrays;  

public class Main  {  

public static void main(String args[])  {  

Scanner input = new Scanner(System.in);

int row, col;  

System.out.print("Rows: ");    row = input.nextInt();

System.out.print("Cols: ");     col = input.nextInt();  

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){    

    for(int j =0;j<col;j++){

        Array2D[i][j] = input.nextInt();  

    }     }

 

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}  

public static int[] findmax(int[][] Array2D,int row, int col)   {  

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

    for(int j =0;j<col;j++){

        if(Array2D[i][j] > max){  

            maxitem[0] = i;

            maxitem[1] = j; } }    }

 

return maxitem;  

}  

}

Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         Array2D[i][j] = input.nextInt();   </em>

<em>     }     } </em>

This calls the findmax function. The returned array of the function is saved in maxarray  

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}  

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col)   {  

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

7 0
3 years ago
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