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morpeh [17]
3 years ago
12

What is the answer to X+2y=6

Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0

\text{Turn the equation into slope intercept form}\\\\\text{Slope intercept form: y = mx + b}\\\\\text{Solve:}\\\\x+2y=6\\\\\text{Subtract x from both sides}\\\\2y=-x+6\\\\\text{Divide both sides by 2}\\\\\boxed{y=-\frac{1}{2}x+3}

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Consider the line integral Z C (sin x dx + cos y dy), where C consists of the top part of the circle x 2 + y 2 = 1 from (1, 0) t
pashok25 [27]

Direct computation:

Parameterize the top part of the circle x^2+y^2=1 by

\vec r(t)=(x(t),y(t))=(\cos t,\sin t)

with 0\le t\le\pi, and the line segment by

\vec s(t)=(1-t)(-1,0)+t(2,-\pi)=(3t-1,-\pi t)

with 0\le t\le1. Then

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)

=\displaystyle\int_0^\pi(-\sin t\sin(\cos t)+\cos t\cos(\sin t)\,\mathrm dt+\int_0^1(3\sin(3t-1)-\pi\cos(-\pi t))\,\mathrm dt

=0+(\cos1-\cos2)=\boxed{\cos1-\cos2}

Using the fundamental theorem of calculus:

The integral can be written as

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=\int_C\underbrace{(\sin x,\cos y)}_{\vec F}\cdot\underbrace{(\mathrm dx,\mathrm dy)}_{\vec r}

If there happens to be a scalar function f such that \vec F=\nabla f, then \vec F is conservative and the integral is path-independent, so we only need to worry about the value of f at the path's endpoints.

This requires

\dfrac{\partial f}{\partial x}=\sin x\implies f(x,y)=-\cos x+g(y)

\dfrac{\partial f}{\partial y}=\cos y=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\sin y+C

So we have

f(x,y)=-\cos x+\sin y+C

which means \vec F is indeed conservative. By the fundamental theorem, we have

\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=f(2,-\pi)-f(1,0)=-\cos2-(-\cos1)=\boxed{\cos1-\cos2}

3 0
3 years ago
Select the expressions that are equivalent to 2(9r)
pashok25 [27]

Answer:

18r

Step-by-step explanation:

Multiply 9 by 2

5 0
3 years ago
Help pls haha also Merry Christmas
MArishka [77]

Answer:

x = √39

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Identify</u>

Leg <em>a</em> = <em>x</em>

Leg <em>b</em> = 5

Hypotenuse <em>c</em> = 8

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [PT]:                     x² + 5² = 8²
  2. Isolate <em>x</em> term:                       x² = 8² - 5²
  3. Exponents:                            x² = 64 - 25
  4. Subtract:                               x² = 39
  5. Isolate <em>x</em>:                               x = √39
3 0
3 years ago
Read 2 more answers
Find the volume of the region bounded above by the elliptical paraboloid zequals=9 minus 4 x squared minus 5 y squared9−4x2−5y2
Virty [35]

Answer:

\int\limits^1_0 \int^1_0{z} \, dA

Step-by-step explanation:

\int\limits^1_0\int^1_0 {9-4x^2-5y^2dy} \, dx

\int\limits^1_0 {9y-4x^2y-\frac{5y^3}{3}|_0 ^1 } \, dx

\int\limits^1_0 {22/3 -4x^2} \, dx

You finish the leftover.

7 0
3 years ago
in a circle, a 60° sector has an area of a 36π cm^2. find the radius of the circle. round your answer to the nearest whole centi
hammer [34]
Area of circle = \frac{ \theta }{360^o}  \times \pi r^2 \\ 36 \pi = \frac{60^o}{360^o}  \times \pi r^2 \\ r^2=216 \\ r= \sqrt{216} =14.70 \ cm \\ r=15 \ cm \ to \ the \ nearest \ whole \ centimeter.
3 0
3 years ago
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