All categories

3 years ago

Omar spends 19 hours in a 2-weeks practicing his tuba skills. How many hours does he practice in 7 weeks

Mathematics

2 answers:

Tom [10]3 years ago

6 0

Answer:

x= 66.5

Step-by-step explanation:

First you write them down like this:

Hours Weeks

19 - 2

x - 7

2.Then you cross multiply, to make an equation so the equation will be:

2x=19*7

3.Then19*7 is 133 so then the equation gets simplified to:

2x=133

4.Now you divide both sides by 2 because that is how many x's there are.so it will be 133/2=66.5 and the equation is now completed to x= 66.5 !

OlgaM077 [116]3 years ago

3 0

Answer:

Step-by-step explanation:

I would take 19hours/2weeks=9.5 hours a week than 9.5hours a week times 7 weeks equal 66.5 hours in 7 weeks

Answer 66.5 hours

You might be interested in

Help pls I need it now

Naddik [55]

Answer and Step-by-step explanation:

So, the format you should choose is the second one.

This is what goes in each box:

[4] (p - [6]) = [12]

The 4 is multiplying the price for 1 of the items (and it is 4 because there are 4 items), the 6 is taking away 6 dollars (because coupons take away money from amount) and 12 is the total amount of money.

Now, we solve for p.

Divide each side by 4.

p - 6 = 3

Now, add 6 to each side.

p = 9.

Each item cost 9 dollars.

#teamtrees #PAW (Plant And Water)

8 0

3 years ago

Deluxe River Cruises operates a fleet of river vessels. The fleet has two types of vessels: A type-A vessel has 60 deluxe cabins

bixtya [17]

Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.

Step-by-step explanation: As it is stipulated, x relates to type-A and y to type-B.

Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:

60x + 80y ≤ 360

For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:

160x + 120y ≤ 680

To calculate how many of each type you need:

60x + 80y ≤ 360

160x + 120y ≤ 680

Isolating x from the first equation:

x = $\frac{360 - 80y}{60}$

Substituing x into the second equation:

160( $\frac{360 - 80y}{60}$ ) + 120y = 680

-3200y+1800y = 10200 - 14400

1400y = 4200

y = 3

With y, find x:

x = $\frac{360 - 80y}{60}$

x = $\frac{360 - 80.3}{60}$

x = 2

To determine the cost:

cost = 42,000x + 51,000y

cost = 42000.2 + 51000.3

cost = 161400

To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400

8 0

2 years ago

the 5th and 6th grade students at jackson middle school are going on a field trip. there are 6 classes in the fitth grade, and e

Mariulka [41]

No because there are 20 multiplied by 3 is 60. So the answer would be 60+144=204x12=2448 but the last answer was still correct

4 0

2 years ago

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

klemol [59]

Answer:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

Step-by-step explanation:

Given the expression

$\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)$

Remove parentheses: (a)=a

$=-t^4-5t^3-10t^2+9t^3+3t^2-1$

Group like terms

$=-t^4-5t^3+9t^3-10t^2+3t^2-1$

Add similar elements

$=-t^4-5t^3+9t^3-7t^2-1$ ∵ $-10t^2+3t^2=-7t^2$

Add similar elements

$=-t^4+4t^3-7t^2-1$ ∵ $-5t^3+9t^3=4t^3$

Thus, the equivalent expression in simplified form:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

4 0

3 years ago

Rewrite in simplest terms:

tangare [24]

Answer:

If one −5s−7(8s−1): -61s+7

If two −5s−7(8s−1): -112s+14

Step-by-step explanation:

-5s-7(8s-1)

Multiply -7 onto 8s and -1:

-5s-56s+7

add -5s and -56s:

-61s+7

−5s−7(8s−1)−5s−7(8s−1)

Multiply both -7 to 8s and -1

-5s-56s+7-5s-56s+7

add:

-112s+14

6 0

3 years ago