Answer: 5 times
Step-by-step explanation:
Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:
For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:
R = 12R'
R = 12(-2, -4)
R = (-24, -48)
For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:
T = 12T'
T = 12(4, 4)
T = (48, 48)
Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)
Answer:
parallel : y = -3x + 3
perpendicular : y = 1/3x + 3
Step-by-step explanation:
rewrite 3x + y - 3 = 0
y = -3x + 3
parallel has the same slope
so
parallel : y = -3x + 3
perpendicular is negative reciprocal of the slope
so
-3x becomes 1/3x
so
perpendicular : y = 1/3x + 3
