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nata0808 [166]
3 years ago
10

I nedd help on this please

Mathematics
1 answer:
inysia [295]3 years ago
5 0

Answer:

c  sqrt( ( x2-x1) ^2 + ( (y2-y1) ^2)

Step-by-step explanation:

The distance formula is

d = sqrt( ( x2-x1) ^2 + ( (y2-y1) ^2)

It is the difference between the coordinates.  It is based on the Pythagorean theorem

You might be interested in
Find the values of the pronumerals in this diagram. Write down the reason in each case.
timofeeve [1]

Answer:

see explanation

Step-by-step explanation:

a and 85 form a straight angle and are supplementary, thus

a + 85 = 180 ( subtract 85 from both sides )

a = 95

b and 85 are vertical angles and are congruent, thus

b = 85

c and 85 are corresponding angles and congruent, thus

c = 85

c and d are vertical angles and congruent, thus

d = 85

In conclusion

a = 95, b = 85, c = 85, d = 85

5 0
3 years ago
On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, ne
Mrrafil [7]
<h3>Answer:  Choice C.   (1,0)</h3>

============================================================

Explanation:

Point H is at (-2,2) and J is at (4,-2)

Focusing on the x coordinates, the midpoint is (x1+x2)/2 = (-2+4)/2 = 1.

The y coordinates have a midpoint of (y1+y2)/2 = (2+(-2))/2 = 0.

The midpoint is at (1,0). That's why the answer is choice C.

--------------------------

This next section is optional.

Points I and K are located at (4,3) and (-2,-3) respectively

Averaging the x coordinates gets us (x1+x2)/2 = (4+(-2))/2 = 1

Doing the same for the y coordinates gets us (y1+y2)/2 = (3+(-3))/2 = 0

We end up with the same midpoint (1,0)

The midpoint being the same for both diagonals proves that each diagonal is bisected, ie cut in half.

3 0
3 years ago
Find equations for those tangent lines to<br> the graph of<br> y = x − 3/x
pychu [463]

Step-by-step explanation:

y=X -3/X

y=X/1 -3/x

y= 2x -3/x

y*X= 2x-3

y*X/2 = x-3

7 0
3 years ago
Examine the pattern in the powers of i you wrote in the table, and create a rule for finding the value of large powers of i. Jus
denpristay [2]
Let N be any integer. Then

i^N=\begin{cases}1&\text{if }N\equiv0\mod4\\i&\text{if }N\equiv1\mod4\\-1&\text{if }N\equiv2\mod4\\-i&\text{if }N\equiv3\mod4\end{cases}

In other words:

(1) If N is a multiple of 4, then i^N=1.

(2) If dividing N by 4 leaves a remainder of 1, then i^N=i, since i^N=i^{4n+1} for some integer n, and from (1) we know that i^{4n+1}=i^{4n}i=i (because, obviously, 4n is a multiple of 4).

(3) If instead you get a remainder of 2, then i^N=-1. This follows from (1) as well. i^N=i^{4n+2}=i^{4n}i^2=(1)(-1)=-1.

(4) Finally, if you get a remainder of 3, then i^N=i^{4n+3}=i^{4n}i^2i=(1)(-1)(i)=-i.
5 0
3 years ago
An equation is written to represent the relationship between the temperature in Alaska during a snow storm, y, as it relates to
baherus [9]
The x axis represents time so it can only have positive values.

That means that the quadrant 2 and quadrant 3 are not used.

Given that the temperature (y-axis) can be positive or negative the values are in the quadrants 1 and 4.

Therefore, the answer is Quadrant 1 and 4 only.
3 0
3 years ago
Read 2 more answers
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