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3 years ago

How do you simplify 4/42

Mathematics

2 answers:

kolbaska11 [484]3 years ago

3 0

Answer:

4/42 = 2/21 when simplified down

Step-by-step explanation:

Cancel the common factor: 2

=2/21

jarptica [38.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

$\frac{4}{42}\\\\\mathrm{Cancel\:the\:common\:factor:}\:2\\\\=\frac{2}{21}\\\\\left(\mathrm{Decimal:\quad }\:0.09523 \right)$

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2 3/4 qt = how many pt

timofeeve [1]

2pt=1qt
1pt=1/2qt
therefor
multiply 2 and 3/4 by 1/2
(2 and 3/4) times 1/2=(2+3/4) times 1/2=2 times 1/2+3/4 times 1/2=2/2+3/8=1+3/8=1 and 3/8 pt

4 0

3 years ago

7. Solve the formula M=2P+3Q for the variable Q.

vichka [17]

The answer is <span>Q=(M−2P)/3
</span>
<span>M = 2P + 3Q

Subtract 2P from both sides:
M - 2P = 2P + 3Q - 2P
M - 2P = 3Q

Divide both sides by 3:
(M - 2P)/3 = 3Q/3
(M - 2P)/3 = Q</span>

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2 years ago

A high speed train travels a distance of 503 km in 3 hours.

Marta_Voda [28]

Step-by-step explanation:

it's is 2.8 km if we round to one decimal place

4 0

2 years ago

A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r

eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

Radius= 1.5 m

Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= $2\pi rh$

Considering, π= 3.14

⇒ lateral surface area of cylinder= $2\times 3.14\times 1.5\times 2.5$

⇒ lateral surface area of cylinder= $23.55 \ m^{2}$

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= $\frac{16500}{23.55} = 700.6369 \approx 701$

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

8 0

3 years ago

Points F,G, and H are collinear such that FG:FH=2/3.If a directed line segment begins at F(-3,2) and ends at H (-3,7), find the

Nana76 [90]

We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates:
FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3
x + 3 = (2/3)(6)
x = 1
For the y-coordinates:
FG/FH = (y - 2) / (7 - 2) = 2/3
y - 2 = (2/3)(5)
y = 16/3
Therefore the coordinates of G are (1, 16/3).

8 0

3 years ago