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SCORPION-xisa [38]
3 years ago
10

The number of wolves in a wildlife refuge can be modeled by an exponential function where x is the number of decades since popul

ation counts began and y is the average annual number of wolves during the decade is given in the table
WHICH GRAPH IS THE GRAPH OF THE FUNCTION??
Mathematics
1 answer:
WINSTONCH [101]3 years ago
8 0
You didn’t even show the graphs tho
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Answer:

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3 years ago
What the answer X/3=3
galina1969 [7]

Answer:

x = 9

Step-by-step explanation:

Isolate the variable. Note the equal sign, what you do to one side, you do to the other. Multiply 3 to both sides.

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x = 3(3)

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A student solved this problem by working backward. Jared has some flowers. He has 6 more red flowers than yellow flowers. He has
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3 years ago
What is 280.0575 as a fraction
LUCKY_DIMON [66]

Answer...

280\frac{23}{400}

Steps....

1) Rewrite the decimal number as a fraction with 1 in the denominator

2) Multiply to remove 4 decimal places. Here, you multiply top and bottom by 10^{4} = 10000

3) Find the Greatest Common Factor (GCF) of 2800575 and 10000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 25

4) Simplify the improper fraction!

8 0
2 years ago
Read 2 more answers
Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v
olga_2 [115]

We are given

f=z^3 -x^2y

Firstly, we can find gradient

so, we will find partial derivatives

f_x=0 -2xy

f_x=-2xy

f_y=0 -x^2

f_y=-x^2

f_z=3z^2

now, we can plug point (-5,5,2)

f_x=-2*-5*5=50

f_y=-(-5)^2=-25

f_z=3(2)^2=12

so, gradient will be

gradf=(50,-25,12)

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}

|v|=\sqrt{29}

now, we can find unit vector

v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

now, we can find dot product to find direction of the vector

dir=(gradf) \cdot (v')

now, we can plug values

dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })

dir=-\frac{248\sqrt{29}}{29}.............Answer



7 0
3 years ago
Read 2 more answers
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