(4x + 3y)(4x − 3y) = (4x)^2 -12xy + 12xy - (3y)^2 =
16x^2 - 9y^2
4
I HAVE TO WRITE STUFF OR ELSE IT WON;T LET ME POST YOUR ANSWER IS 4
Answer: <span>A. about 30.8 miles
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The x and y distance from the campsite at A (3, – 5), and the next checkpoint station is located at B (–10, 1) would be:
Xab= Xb- Xa= -10 - 3= -13
Yab= Yb- Ya= 1- (-5)= 6
The resultant distance would be
c^2= a^2+b^2
c^2= (-13)^2 + (6)^2
c= </span>√(169+36)= √205
c=14.32
If each unit in the coordinate plane represents 2.15 miles, the true distance= 14.32*2.15 miles= 30.78 miles
Answer:
f(0) = 2
Step-by-step explanation:
Read from the graph the value "y" that the line presents when "x" is zero. That is the f(0) you are looking for.
See attached screen capture with the point highlighted
f(0) according to the image provided is equal to 2.
f(0) = 2