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Leni [432]
3 years ago
11

Which sequence of transformations proves that shape I is similar to shape II?

Mathematics
2 answers:
4vir4ik [10]3 years ago
4 0
Note that if you simply reflected it and dilated it, it would be too far to the left

note that the distances bewteen the axises in image 1 were 1 and 3in image 3,the distances are 2 and 6
seems to be 3 times
so it's the 90 counterclockwise rotation and dilation by scale factor of 3
answer is last one

Travka [436]3 years ago
4 0

Answer:

The correct answer is C not D, because I got it right with C on PLATO.

Step-by-step explanation:

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6. Solve using any method.<br> x+6y=7<br> 5x + 8y = 13
Norma-Jean [14]

Answer:

<h2>x = 1, y = 1 → (1, 1)</h2>

Step-by-step explanation:

\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}x+6y=7&\text{Multiply both sides by (-5)}\\5x+8y=13\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-5x-30y=-35\\5x+8y=13\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-22y=-22\qquad\text{divide both sides by (-22)}\\.\qquad\boxed{y=1}\\\\\text{Put it to the first equation}\\\\x+6(1)=7\\x+6=7\qquad\text{subtract 6 from both sides}\\\boxed{x=1}

\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}x+6y=7&\text{subtract}\ 6y\ \text{from both sides}\\5x+8y=13\end{array}\right\\\\\left\{\begin{array}{ccc}x=7-6y&(1)\\5x+8y=13&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\5(7-6y)+8y=13\qquad\text{use the distributive property}\\(5)(7)+(5)(-6y)+8y=13\\35-30y+8y=13\qquad\text{subtract 35 from both sides}\\-30y+8y=13-35\qquad\text{combine like terms}\\-22y=-22\qquad\text{divide both sides by (-22)}\\\boxed{y=1}

\text{Put it to (1):}\\\\x=7-6(1)\\x=7-6\\\boxed{x=1}

4 0
3 years ago
Read 2 more answers
What is 4 5/6 multiplied by 3 as a mixed number or fraction
KIM [24]

Answer:

14 1/2

Step-by-step explanation:

4 5/6 * 3 = 14 1/2


mark brainliest  :)

6 0
3 years ago
PLEASE ANSWER THIS QUESTION ASAP!!!!
Zanzabum

Answer:

B, y is the greater number than every x.

Step-by-step explanation:

8 0
3 years ago
Sprint to the finish the professional cyclist travels 380 meters in 20 seconds. At that rate how far does the cyclist travel in
kumpel [21]

Answer:

57 meters

Step-by-step explanation:

we know that

Sprint to the finish the professional cyclist travels 380 meters in 20 seconds

so

using proportion

Find out how far does the cyclist travel in 3 seconds

Let

x -----> the distance in meters

\frac{380}{20}\frac{m}{sec}=\frac{x}{3}\frac{m}{sec}\\\\x=380(3)/20\\\\x=57\ m

3 0
3 years ago
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gogolik [260]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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