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3 years ago

11

Which sequence of transformations proves that shape I is similar to shape II?

2 answers:

4vir4ik [10]3 years ago

4 0

Note that if you simply reflected it and dilated it, it would be too far to the left

note that the distances bewteen the axises in image 1 were 1 and 3in image 3,the distances are 2 and 6
seems to be 3 times
so it's the 90 counterclockwise rotation and dilation by scale factor of 3
answer is last one

Travka [436]3 years ago

4 0

Answer:

The correct answer is C not D, because I got it right with C on PLATO.

Step-by-step explanation:

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to fi

Keith_Richards [23]

Answer:

P(X = 12) = 0.0064.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 30, p = 0.2$

We want P(X = 12). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 12) = C_{30,12}.(0.2)^{12}.(0.8)^{18} = 0.0064$

P(X = 12) = 0.0064.

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2 years ago

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Answer:

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2 years ago