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Artyom0805 [142]
3 years ago
9

What property is -2.1×1= -2.1 ?

Mathematics
1 answer:
3241004551 [841]3 years ago
8 0
Multiplicative Identity Property.

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Write an equation for a line parallel to y=−4x+5 and passing through the point (4,-21)
Sindrei [870]

Answer:

Y=-4x-5

Step-by-step explanation:

-21=-4(4)+b

-21=-16+b

b=-5

y=-4x-5

3 0
3 years ago
Read 2 more answers
6.
abruzzese [7]

Answer:

10.50

Step-by-step explanation:

7 0
3 years ago
Help pls you get 27 points
Trava [24]

Answer:

C. [-5] < [-3]   ||   D. [-4] < [-2]

Step-by-step explanation:

in A. 5 should be greater, > than -3

in B. 2 should be greater, > than -4

in C. its correct answer. true statement.

in D.  its correct answer. true statement.

5 0
2 years ago
Point M (-3, 5) is translated using this rule. (x, y) ----&gt; (x - 1, y) What are the coordinates of M'?
Nuetrik [128]

Answer:

The coordinates of point M' are M'(x,y) = (-4, 5).

Step-by-step explanation:

According to the statement, we have the following translation rule:

M'(x,y) = M(x,y) + (-1, 0) (1)

Where:

M(x,y) - Original point.

M'(x,y) - Translated point.

(-1, 0) - Translation vector.

If we know that M(x,y) = (-3, 5), then the coordinates of the point M' are:

M'(x,y) = (-3,5) + (-1,0)

M'(x,y) = (-4, 5)

The coordinates of point M' are M'(x,y) = (-4, 5).

5 0
3 years ago
15 points!!! GEOMETRY help please!!<br> Questions attached!
dolphi86 [110]
3. Look at the picture.

We have the right angle triangle. We know the sum of measures of angles in triangle is equal 180°. Therefore:

x^o+90^o+43^o=180^o\\\\x^o+133^o=180^o\ \ \ |-133^o\\\\x^o=47^o

Answer:\ \boxed{47^o}

4.
Look at the picture.

Use Pythagorean theorem:

x^2+14^2=(10+x)^2\\\\x^2+196=10^2+2\cdot10\cdot x+x^2\ \ \ \ |-x^2\\\\196=100+20x\ \ \ |-100\\\\20x=96\ \ \ |:20\\\\x=4.8

Used:\ (a+b)^2=a^2+2ab+b^2

Answer:\ \boxed{4.8\ units}

5.
TRUE: 1; 2; 4

6.
We find a slope of the line OP:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\O(2;\ 6)\to x_1=2;\ y_1=6\\\\P(4;\ 3)\to x_2=4;\ y_2=3\\\\m=\dfrac{3-6}{4-2}=\dfrac{-3}{2}

We have: OP:\ y=-\dfrac{3}{2}x+b

Now, we must find the slope of the line perpendicular to the line OP.
We know:

k:y=m_1x+b;\ l:y=m_2x+c\\\\k\ \perp\ l\iff m_1m_2=-1

therefore

-\dfrac{3}{2}m_2=-1\ \ \ |\cdot\left(-\dfrac{2}{3}\right)\\\\m_2=\dfrac{2}{3}

So. We have the answer! :)

Answer:\ \boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}}

6 0
3 years ago
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