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Ksivusya [100]
3 years ago
13

At 8:45 p.m., a jet is located 64 mi due east of a city. A second jet is located 57 mi due north of the city. To the nearest ten

th of a mile, what is the distance between the two jets? Enter your answer as a decimal in the box.
(If you can provide the answer it would help. I just need to understand how to solve for this!)
Mathematics
2 answers:
alukav5142 [94]3 years ago
7 0
85.7 is your answer cause i took the test btw srry this late answer
MissTica3 years ago
5 0
If we connect the location of the two jets and the distances they have traveled, we form a right triangle. The distance between the two jets is the hypotenuse of the right triangle. Using Pythagorean theorem,
                         h² = a² + b²
where a and b are the distances they have traveled. 
                                   h² = (64 mi)² + (57 mi)²
The value of h is equal to 85.71 mi. Thus, the distance between the two jets is approximately 85.71 miles. 
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Tyrone wrote an equivalent expression for 28 + x - 2n + 7 - n - 5x + 4. His equivalent expression was -3n - 5x + 39 + x. What er
MA_775_DIABLO [31]

Answer with Step-by-step explanation:

We are given an expression:

28 + x - 2n + 7 - n - 5x + 4

We have to find its equivalent expression

On combining the like terms of the above expression

28+4+7+x-5x-2n-n

= 39-4x-3n

= -3n-4x+39

According to Tyrone the equivalent expression was:

-3n - 5x + 39 + x

The error Tyrone made was:

A. Tyrone neglected to combine the x terms

6 0
3 years ago
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True [87]

Answer:

1) No

2) No

3) Yes

4)Yes

5) No

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Step-by-step explanation:

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Hope it helps!

4 0
3 years ago
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Maurinko [17]

Answer:

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Step-by-step explanation:

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Please help me with this homework
lorasvet [3.4K]
You get the final solution. You wouldn’t need to simplify anything
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