Question

At 8:45 p.m., a jet is located 64 mi due east of a city. A second jet is located 57 mi due north of the city. To the nearest tenth of a mile, what is the distance between the two jets? Enter your answer as a decimal in the box.
(If you can provide the answer it would help. I just need to understand how to solve for this!)

Answer 1

85.7 is your answer cause i took the test btw srry this late answer

Answer 2

If we connect the location of the two jets and the distances they have traveled, we form a right triangle. The distance between the two jets is the hypotenuse of the right triangle. Using Pythagorean theorem,
                         h² = a² + b²
where a and b are the distances they have traveled. 
                                   h² = (64 mi)² + (57 mi)²
The value of h is equal to 85.71 mi. Thus, the distance between the two jets is approximately 85.71 miles.