Question

Solve:::::::::::::::: id="TexFormula1" title=" \sf \: 3(y + 3) - 10 = 2y + 1" alt=" \sf \: 3(y + 3) - 10 = 2y + 1" align="absmiddle" class="latex-formula">
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Answer 1

$\sf{\pmb{ANSWER : }}$

let the equation be

$\sf \: 3(y + 3) - 10 = 2y + 1$

$\sf \: 3y + 9 - 10 = 2y + 1$

$\sf \: 3y - 1 = 2y + 1$

$\sf \: 3y -2y = 1 + 1$

$\purple {{{\sf y = 2 }}}$

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Answer 2

Solution:

3(y + 3) - 10 = 2y + 1

• Let us first multiply 3 and (y + 3).

or, 3y + 9 - 10 = 2y + 1

• Now, transpose the value of 2y to the left hand side and 9 and -10 to the right hand side.

or, 3y - 2y = 1 - 9 + 10

• Do the addition and subtraction.

or, y = 2

• So, we have got the value of y.

Verification:

LHS

= 3 (2 + 3) - 10

= 3 (5) - 10

= 15 - 10

= 5

RHS

= 2 (2) + 1

= 4 + 1

= 5

So, LHS = RHS [verified]

Answer:

y = 2

Hope you could understand.

If you have any query, feel free to ask.