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Margaret [11]
3 years ago
11

Can someone help with this please?

Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0
Which question do you need help with? 
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The original price of a video game is $32.99 before tax. When Mario bought the video game it rang up as $26.39 before tax. He th
mihalych1998 [28]

Answer:

Part A: The percent discount on game is 20%.

Part B: Mario paid a total of $28.50 including sales tax.

Step-by-step explanation:

Given that:

Part A:

Original price of video game = $32.99

Discounted price = $26.39

Amount of discount = 32.99 - 26.39 = $6.60

Discount percent = \frac{Amount\ of\ discount}{Original\ price}*100

Discount percent = \frac{6.60}{32.99}*100 = 0.20*100

Discount percent = 20%

Part B:

Sales tax = 8% of discounted price

Amount of sales tax = \frac{8}{100}*26.39 = 0.08*26.39

Amount of sales tax = $2.11

Total amount = $26.39 + $ 2.11 = $28.50

Hence,

Part A: The percent discount on game is 20%.

Part B: Mario paid a total of $28.50 including sales tax.

5 0
3 years ago
One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.
vampirchik [111]
◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
5 0
3 years ago
Translate the sentence into an equation. Four more than the quotient of a number and 8 is 9. Use the variable y for the unknown
Virty [35]
Equation : 4+( y/8) = 9
8 0
3 years ago
We have 5 circles surrounding a circle, Is there enough room to fit one more circle
Alexus [3.1K]

Answer:

Definitely

Step-by-step explanation:

In order to completely surround a circle, you need six circles to do that while here in the question it is mentioned that currently there are only five circles surrounding the circle, hence there is enough room to easily fit one more circle.

I just hope that you are satisfied with the answer, Best of Luck.

4 0
3 years ago
(x+1)^2-(x-1)^2 dont kbow what to do
marshall27 [118]

Use this formula a2 − b2 = (a + b)(a − b)

<span>(x+1)^2-(x-1)^2  in this case, a = x+1, b = x-1</span>

<span>= [(x+1) + (x-1)] *  [(x+1) – (x-1)]</span>

=(x +1 + x – 1) *(x +1 – x +1)

= 2x * 2

<span>=4x</span>

6 0
3 years ago
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