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sergiy2304 [10]
3 years ago
15

What is the slope of the line that passes through (3, -7) and (-1, 1)?

Mathematics
1 answer:
Andru [333]3 years ago
6 0

(3, -7) and (-1, 1)

To find slope of a line using 2 points

we use formula

\frac{y_2 - y_2}{x_2-x_1}

(3, -7) is (x1,y1) and (-1, 1) is (x2,y2)

Here x1= 3  and y1= -7

x2=-1 and y2=1

\frac{1- (-7)}{-1-3}

\frac{8}{-4}=-2

slope   of a line using 2 points (3, -7) and (-1, 1) is  -2


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Which of the relations below is not a function?
Ilia_Sergeevich [38]

Answer:

Relations B and E do not represent the function.

Step-by-step explanation:

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

If we closely observe relation B, and E i.e.

  • B) {(3,4), (4,5), (3,6). (6,7)}
  • E) {(3,4), (4,5), (4,6)}

Relation 'B' IS NOT A FUNCTION

Relation B has duplicated or repeated inputs i.e. x = 3 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.

Thus, relation B is NOT a function.

Relation 'E' IS NOT A FUNCTION

Relation E has duplicated or repeated inputs i.e. x = 4 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.

Thus, relation B is NOT a function.

Therefore, relations B and E do not represent the function.

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If $1000 is invested at 8% interest, compounded annually, then after n years the investment is worthan = 1000(1.08)ndollars.(a)
Luba_88 [7]

Answer:

Diverge

Step-by-step explanation:

(a)

1st year: 1000 * 1.08^1 = \$1080

2nd year: 1000 * 1.08^2 = \$1166.4

3rd year: 1000 * 1.08^3 = \$1259.71

4th year: 1000 * 1.08^4 = \$1360.49

5th year: 1000 * 1.08^5 = \$1469.33

(b) The sequence is divergent, because if we take the derivative of the function with respect to n year:

(1000*1.08^n)^{'} = 1000ln(n)*1.08^n

This is a positive, meaning the slope of the function is positive. If we take the second derivative using product rule

(1000ln(n)*1.08^n)^{'} = 1000\frac{ln(n)}{n}1.08^n

This is also positive when n > 0. Therefore, the slope is positive and increasing. This means the sequence diverges.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
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