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Harlamova29_29 [7]
2 years ago
6

Find the measure of angles a, b, c, d, and e. Only use numbers for your answers.

Mathematics
2 answers:
defon2 years ago
5 0
C:42 and the rest are what the other person said I just checked
Zinaida [17]2 years ago
5 0
Here are the correct answers
mmmmm
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Please help me I'm stuck on this one
Colt1911 [192]
Ok i should know this i had the same test sum goes to 0 5/8 goes to 5/8 and m goes to -5/8 

hope this helps!
6 0
3 years ago
Select all the equations that are equivalent to this equation.<br> 1/4 (8X + 56) = 20<br> 56 + 8X = 80<br> 14 = 20 – 8x<br> 2X +
Leya [2.2K]
1/4(8x+56)=20
1/4(8x)+1/4(56)=20
2x+14=20
2x=20-14
2x=6
X=3
3 0
2 years ago
Simplify the expression
MaRussiya [10]
11) 7 + -10+(4(5+-3)) = 7+-10+8=5

12) (12 +-10)+3x+-1(2x+4x), 12+-10x+3x+-2x+-4x = 12+-13x
5 0
3 years ago
Read 2 more answers
Divide line segments
ser-zykov [4K]

tis noteworthy that the segment contains endpoints of A and C and the point B is in between A and C cutting the segment in a 1:2 ratio,

\bf \textit{internal division of a line segment using ratios} \\\\\\ A(-9,-7)\qquad C(x,y)\qquad \qquad \stackrel{\textit{ratio from A to C}}{1:2} \\\\\\ \cfrac{A\underline{B}}{\underline{B} C} = \cfrac{1}{2}\implies \cfrac{A}{C}=\cfrac{1}{2}\implies 2A=1C\implies 2(-9,-7)=1(x,y)\\\\[-0.35em] ~\dotfill\\\\ B=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill

\bf B=\left(\cfrac{(2\cdot -9)+(1\cdot x)}{1+2}\quad ,\quad \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}\right)~~=~~(-4,-6) \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -9)+(1\cdot x)}{1+2}=-4\implies \cfrac{-18+x}{3}=-4 \\\\\\ -18+x=-12\implies \boxed{x=6} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2\cdot -7)+(1\cdot y)}{1+2}=-6\implies \cfrac{-14+y}{3}=-6 \\\\\\ -14+y=-18\implies \boxed{y=-4}

6 0
3 years ago
Help me for this question ASAP
Ugo [173]

Answer:

Cube

Step-by-step explanation:

The cubed root of 8 = 2 because 2³ = 8.

So 8 is perfect cube.

6 0
3 years ago
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