All categories

3 years ago

Perfective maintenance usually is cost effective ____ the system

Computers and Technology

2 answers:

Svetlanka [38]3 years ago

6 0

Answer:

During the middle of

Explanation:

Perfective maintenance usually is cost effective during the middle of the system.

Anni [7]3 years ago

5 0

Perfective maintenance usually is cost effective during the middle of the system.

You might be interested in

Review the given requirements using the checklist and discover possible problems with them. The following requirements are for a

KATRIN_1 [288]

Answer:

Redundancy

Req. 1 and Req. 3 are seemed to say the same thing. We need to remove the first sentence in Req. 1

Conflict and understandability

Req. 1 states that access is through web browser while Req. 4 states that access is via html. We have to re-write the Req. 3 to make it clear that users do not actually have to write directly html to communicate with the system.

Completeness

Req. 5 states that print out will “mainly” be documents. What else might be printed? What other inputs will be produced?

Either remove mainly or clarify other print out.

What version of html or web browser is assumed in Req. 1 and Req. 3?

Explanation:

5 0

3 years ago

It is not possible to use keywords to search for themes. true or false.

Drupady [299]

False my dude .........................

3 0

3 years ago

What underlying concept is edge computing based on?

guajiro [1.7K]

Answer:

Edge computing was developed due to the exponential growth of IoT devices, which connect to the internet for either receiving information from the cloud or delivering data back to the cloud. And many IoT devices generate enormous amounts of data during the course of their operations.

Explanation:

8 0

2 years ago

Read 2 more answers

Answer the following questions for Web browser and Web server software: 1. What functions should this software application provi

timurjin [86]

Answer:

Explanation:

Functions should a software application provide to keep a web browser secured

1) The web browser should always be updated, so kindly keep the "automatic update" option enable on your browser settings so that whenever the browser gets an update, it will be updated automatically.

2) Always keep the third party cookies disabled because there are so many unauthorized and phishing sites over the internet they may lead the browser unsafe and cause very higher security risk so block all the third party sites and cookies from the browser

Functions should a software application prohibit to keep a web browser secured

1) Do not store passwords on your web browser, deny the "store password" option on your browser settings. Even if you store passwords on your web browser do set a very strong master password to access all the stored passwords.

2) Do not click on unwanted, unknown hyperlinks. There will be many unsolicited attachments, PDFs, DOCs, files, etc over the internet so do not open or download it unnecessarily.

Functions should a software application provide to keep a web server secured

1) Always use an application scanner. Whenever you install or download any new applications do scan the application before accessing it.

2) Install all the security patches because there are more number of hackers over the internet so do not deny installing the security patcheds on time.

Functions should a software application prohibit to keep a web server secured

1) When an application is not in use for long time, better uninstall it because they are actually of no use so do uninstall all the unwanted softwares or applications along with extensions.

2) There may be scripts, files, setups, codes stored on the web server unknowingly so do check it and delete all the sample scripts, files and codes from the web server.

5 0

3 years ago

Convert infix to postfix

kvv77 [185]

Answer:

static int checkSymbol(char ch)

{

switch (ch)

{

case '+':

case '-':

return 1;

case '*':

case '/':

return 2;

case '^':

return 3;

}

return -1;

}

static String convertInfixToPostfix(String expression)

{

String calculation = new String("");

Stack<Character> operands = new Stack<>();

Stack<Character> operators = new Stack<>();

for (int i = 0; i<expression.length(); ++i)

{

char c = expression.charAt(i);

if (Character.isLetterOrDigit(c))

operands.push(c);

else if (c == '(')

operators.push(c);

else if (c == ')')

{

while (!operators.isEmpty() && operators.peek() != '(')

operands.push(operators.pop());

if (!operators.isEmpty() && operators.peek() != '(')

return NULL;

else

operators.pop();

}

else

{

while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))

operands.push(operators.pop());

operators.push(c);

}

while (!operators.isEmpty())

operands.push(operators.pop());

while (!operands.isEmpty())

calculation+=operands.pop();

calculation=calculation.reverse();

return calculation;

}

Explanation:

Create the checkSymbol function to see what symbol is being passed to the stack.
Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
While the operators is not empty, keep pushing the character to the operators stack.
At last reverse and return the calculation which has all the results.

4 0

2 years ago