Consider the hypothetical study described below. Based solely on the information given, do you have reason to question the resu
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32. (a) For an even function, f(x) = f(-x). Given f(5) = 3, we know f(-5) = 3.
Therefore (-5, 3) is also on the graph.
For an odd function, f(-x) = -f(x). Given f(5) = 3, we know f(-5) = -3.
Therefore (-5, -3) is also on the graph.
33. f(-x) = -f(x). The function is odd.
34. f(-x) = x/(x-1) ≠ -f(x) ≠ f(x). The function is neither even nor odd.
35. f(-x) = f(x). The function is even.
Therefore (-5, 3) is also on the graph.
For an odd function, f(-x) = -f(x). Given f(5) = 3, we know f(-5) = -3.
Therefore (-5, -3) is also on the graph.
33. f(-x) = -f(x). The function is odd.
34. f(-x) = x/(x-1) ≠ -f(x) ≠ f(x). The function is neither even nor odd.
35. f(-x) = f(x). The function is even.
<h2>Answer:</h2>
A.) {-6, -2, 5}
<h2>Step-by-step explanation:</h2>A function from a set
to a set
is a relation that assigns to each element
in the set
exactly one element
in the set
. The set
is the domain (also called the set of inputs) of the function. From the figure, we can see that this set is the x-coordinate of each red point. So this set is {-6, -2, 5}