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Effectus [21]
3 years ago
14

The point of concurrency of the medians of a triangle is called the

Mathematics
1 answer:
tangare [24]3 years ago
8 0

Answer:

centroid of the triangle

Step-by-step explanation:

centroid of the triangle

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18x=36 with a full explanation and I will give you brainlyest
iris [78.8K]

Answer:−18x>36

Divide both sides by −18. Since −18 is negative, the inequality direction is changed.

x< −18

36

​

Divide 36 by −18 to get −2.

x<−2

Step-by-step explanation:

Hope this helps!

5 0
2 years ago
Someone help me plzzz:((((
mash [69]

Step-by-step explanation:

OI= 3.2 cm (same as OH)

To find GI, use Pythagoras Theorem (a²+b²= c²)

6.8²+3.2²= 56.48

√56.48= 7.5 cm

hope it helps! please mark me brainliest

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3 0
3 years ago
Read 2 more answers
Expand and combine like terms.<br> (3c^4-5c^6)^2
lora16 [44]

Answer:

9c^{8} -30c^{10} + 25c^{12}

Step-by-step explanation:

We can use formula (a-b)² = a² -2ab + b².

In our example a = 3c^4 and b = 5c^6

(3c^{4} - 5c^{6})^{2} = [3c^{4} ]^{2} - 2*3c^{4} *5c^{6} + [5c^{6}]^{2}=\\=9c^{8} -30c^{10} + 25c^{12}

4 0
3 years ago
0.62 as a percent <br> (STEP BY STEP)
jolli1 [7]

Answer:

0.62 = 0.62 × 100/100 = (0.62 × 100)/100 = 62/100 = 62%;

In other words:

1) Multiply that number by 100.

2) Add the percent sign % to it.

3 0
3 years ago
Read 2 more answers
An education researcher claims that 58​% of college students work​ year-round. In a random sample of 400 college​ students, 232
Hatshy [7]

Answer:

The proportion of college students who work​ year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58​% of college students work​ year-round.

A random sample of 400 college​ students, 232 say they work​ year-round.

To test the researcher's claim use a one-proportion <em>z</em>-test.

The hypothesis can be defined as follows:

<em>H</em>₀: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> = 0.58.

<em>Hₐ</em>: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> ≠ 0.58. C

Compute the sample proportion as follows:

 \hat p=\frac{232}{400}=0.58

Compute the test statistic value as follows:

 z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

 p-value=2\times P(z

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work​ year-round is 58%.

6 0
4 years ago
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