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Debora [2.8K]
3 years ago
6

What is the value of each digit in 28.6597

Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

1. 20 (tens)

2. 8 (ones)

3. 0.6 (tenths)

4. 0.005 (Hundredths)

5. 0.0009 (thousandths)

6. 0.00007 (ten thousandths)

i hoped this helped!

Step-by-step explanation:

Aleks04 [339]3 years ago
3 0

Answer:

behind the decimal the first digit would be the tens place, then after that those would be the hundredths, the thousands, and the ten thousandths.

Step-by-step explanation:

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Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),
amm1812

Answer:

Step-by-step explanation:

Approximate the integral \int\int\limits_R {f(x,y)} \, dA by dividing the region R with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum \sum\limits^8_{i=1}f(x_i,y_i)\delta A_i

Since all are equal squares, so \delta A_i=1 for every i

\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24

Thus, \sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24

Evaluating the iterate integral \int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.

Thus, \int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=24

7 0
3 years ago
How do i solve these and graph them ?!
Ainat [17]
Use Desmos. It is good.

Here is the graph.
https://www.desmos.com/calculator/wq4kzps9fq

To change the color, you have to click on the line next to the formula for a long time. A window will pop up so you can change the color.
4 0
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